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3 years ago

A=6 cm,b=9cm,and c =3 cm

1 answer:

4 0

The lengths of sides a and c add to 9 cm, the length of side b.
In a triangle, the the sum of the lengths of any two sides must be greater than the the length of the third side. These dimensions do not make a triangle.

Is this really what you meant? Why did you use capital A for a side? Or is A an angle, and it measures 6 deg, not 6 cm?

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1. Choose the correct answer.

Margaret [11]

Answer:

Equilateral triangle

Step-by-step explanation:

equilateral triangle is a triangle in which all three sides have the same length

6 0

3 years ago

A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimat

Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

For this problem, we consider that we want it to be within 4%.

Item a:

The sample size is <u>n for which M = 0.04.</u>

There is no estimate, hence $\pi = 0.5$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2$

$n = 600.25$

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is $\pi = 0.96$ , hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}$

$0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}$

$\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}$

$(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2$

$n = 92.2$

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to $\pi = 0.5$ , the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151

8 0

2 years ago

1. 100 students who are in 9th or 10th grade were asked if they participated in at least one extracurricular activity (sports, m

Marianna [84]

I can not set up a 2 way table online but what they want is a collom of the information neatly laid out...

With the 9th graders in one collom and the 10th graders in the other

like this

                   9th grader   10th grader
# of students    32                      40
# of participated 32                      18

Draw this out with lines and it will be correct.

I hope this helps GOOD LUCK...this is tough math for a middle schooler.

5 0

4 years ago

3(4x +5y) i need help on this lol thanks

Digiron [165]

Answer: 12x+15y

Step-by-step explanation:

5 0

3 years ago

You are painting the outside of a 28 foot fence that goes around a square garden there are four equal sections you have painted

Ratling [72]

4/2 or or 1/2 the job in other words 28 ft

7 0

3 years ago