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2 years ago

Plss helpp me with thiss!! QUESTION: create a inequality equation that equals to 19

Mathematics

1 answer:

noname [10]2 years ago

3 0

Answer:

there are many different type of equation we can use to allow X to equal 19 ! Below are some examples ) See if you can come up with some on your own based off of these examples

Step-by-step explanation:

5x=95................Divide both sides b 5
x=19..............there's one for you
1+x-5=15...............combine like terms
x-4=15...................add 4 to both sides

x=19

mark me as a brainlist

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3 years ago

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3 years ago

Sin(18m-12)cos(7m+2)find the value of m

insens350 [35]

Answer:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

Step-by-step explanation:

Solve for m:

-cos(7 m + 2) sin(12 - 18 m) = 0

Multiply both sides by -1:

cos(7 m + 2) sin(12 - 18 m) = 0

Split into two equations:

cos(7 m + 2) = 0 or sin(12 - 18 m) = 0

Take the inverse cosine of both sides:

7 m + 2 = π n_1 + π/2 for n_1 element Z

or sin(12 - 18 m) = 0

Subtract 2 from both sides:

7 m = -2 + π/2 + π n_1 for n_1 element Z

or sin(12 - 18 m) = 0

Divide both sides by 7:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or sin(12 - 18 m) = 0

Take the inverse sine of both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or 12 - 18 m = π n_2 for n_2 element Z

Subtract 12 from both sides:

m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or -18 m = π n_2 - 12 for n_2 element Z

Divide both sides by -18:

Answer: m = -2/7 + π/14 + (π n_1)/7 for n_1 element Z

or m = 2/3 - (π n_2)/18 for n_2 element Z

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3 years ago

5. What is the equation of the tangent line to the circle x^2+y^2=1 through the point (6,0)?

notka56 [123]

Answer:

There is no tangent line of the given circle at (6, 0).

Step-by-step explanation:

Given equation of the circle,

$x^2 + y^2 = 1$

∵ equation of a circle is $(x-h)^2 +(y-k)^2 = r^2$ ,

Where, (h, k) is the center of the circle and r is the radius,

By comparing,

Center of the given circle = (0, 0),

Radius of the circle = 1 unit

Now, check whether point (6, 0) lie on the circle,

if x = 6, $6^2 + y^2 = 1$

$36 + y^2 = 1$

$y^2 = 1- 36$

$y= i\sqrt{35}\neq 0$

i.e., (6, 0) does not lie on the circle,

Hence, there is no tangent line of the given circle at (6, 0).

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3 years ago

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Veseljchak [2.6K]

Answer. :
True

Explanation :
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