Begin by finding the lowest point the quadratic equation can be, the vertex;
x²-1= is just a translation down of the graph x²
vertex; (0, -1) and since the graph of x² would extend to infinity beyond that point, we can say {x| x≥0} for domain and {y| y≥-1}.
For the linear equation, it is possible to have all x and y values, therefore range and domain belong to all real numbers.
Hope I helped :)
Answer:
Step-by-step explanation:
Note that this function is not defined at x = 0; it does have a vertical asymptote which is the line x = 0, as well as a horiz. asymptote which is the line y = 0. This function is odd because the power of x is -1 (a negative odd number). Half the graph appears in Quadrant I: (1, 1), (2, 1/2), (3, 1/3), etc.
The other half is the reflection of the Quadrant I part in the origin, and this is because the function is odd.
Answer:
45 for 5 and 34 for 6.
Step-by-step explanation:
You are just subtracting by 11.
Answer:
Step-by-step explanation:
New height to initial height=
10/4=2.5
New width from initial width should be 5×2.5=12.5inches
Answer:
x=-3
Step-by-step explanation:
