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Serhud [2]
2 years ago
8

Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 4 L, the press

ure is 385 kPa (kilopascals). What is the pressure when the volume is 10 L ?
Mathematics
1 answer:
Anon25 [30]2 years ago
8 0

9514 1404 393

Answer:

  154 kPa

Step-by-step explanation:

The volume and pressure are given as inversely related. The volume increases by a factor of 10/4, so the pressure will decrease by the factor 4/10.

  (4/10)(385 kPa) = 154 kPa

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Lizzie has 30 coins that total $4.80. All of her coins are dimes, D, and quarters, Q. Algebraically determine how many of each t
Gnom [1K]

Lizzie has 18 dimes and 12 quarters

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that LIzzie has 30 coins

number of dimes + number of quarters = 30

d + q = 30 ---- eqn 1

Also given that the coins total $ 4.80

number of dimes x  value of 1 dime + number of quarters x  value of 1 quarter = 4.80

d \times 0.10 + q \times 0.25 = 4.80

0.1d + 0.25q = 4.8 ------ eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 30 - q ---- eqn 3

Substitute eqn 3 in eqn 2

0.1(30 - q) + 0.25q = 4.8

3 - 0.1q + 0.25q = 4.8

0.15q = 1.8

<h3>q = 12</h3>

From eqn 3,

d = 30 - 12

<h3>d = 18</h3>

Thus she has 18 dimes and 12 quarters

6 0
3 years ago
Calcular s, si la figura es un prisma a=15m2, b=20m2
julia-pushkina [17]
Celculate the figures by using the numbers,with letters
6 0
3 years ago
A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether th
ki77a [65]

Answer:

(a) A matched pair design is used to perform the test.

(b) Each sample is of size 30.

(c) The null hypothesis is rejected.

(d) The effect size of the test is medium.

Step-by-step explanation:

A statistical experiment is performed to determine whether the amount of time (in minutes) that parent-child pairs spend on social networking sites to test show any generational differences.

<u>Given</u>:

MD = -42 minutes

t₍₂₉₎ = 4.021

p < 0.05

d = 0.49

The hypothesis is:

<em>H₀</em>: There is no difference between the means, i.e. <em>μ₁</em> = <em>μ₂</em>.

<em>Hₐ</em>: There is a significant difference between the means, i.e. <em>μ₁</em> ≠ <em>μ₂</em>.

(a)

A matched pair design is used to perform the test.

In a matched pair design the participant of the two groups are related in some way. For example, the same sample is tested before and after applying the treatment.

In this case the matched are pairs are of children and their parents. And the treatment is the amount of time spent on social networking sites.

(b)

The degrees of freedom of a matched pair design is:

df = n - 1

29 = n - 1

n = 29 + 1

n = 30

Thus, each sample is of size 30.

(c)

The <em>p</em>-value of the test statistic is < 0.05.

If the <em>p</em>-value is less than the significance level <em>α </em>(say, 0.05) then the null hypothesis is rejected and vise-versa.

Since <em>p</em> < 0.05 the null hypothesis is rejected concluding that there is a significant difference between the amount of time spent on social networking sites by parents and children.

(d)

The estimated value of Cohen's d is, <em>d</em> = 0.49.

A Cohen's d value between the range 0.50 to 0.80 is considered as medium.

Thus, the effect size of the test is medium.

3 0
3 years ago
Javiver has $15 to spend On action figures.If it’s bigger cost two dollars what is the greatest number of action figures he can
FinnZ [79.3K]
7.

15/2= 7.5
you cant get 7 and a half action figures so round down to 7
5 0
3 years ago
I the revenue for the week is $2000, and labor cost consists of two workers earning $8 per hour who work 40 hours each, what is
MA_775_DIABLO [31]

Revenue = $2000


Labour cost = 40 x 8 = $320


Percentage = 320/2000 x 100 = 16%


Answer: 16%

4 0
3 years ago
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