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lana [24]
3 years ago
10

You put $500 in the bank, where it ears 1.5% simple interest every year. How long until your money will triple?

Mathematics
1 answer:
zzz [600]3 years ago
3 0

Answer:

133.33 years

Step-by-step explanation:

Given that:

Principal = $500

Interest rate (r) = 1.5% = 0.015

Triple amount of principal = $500 * 3 = $1500 = final amount (A)

Number of years (t) =?

Using the relation :

A = P(1 + rt)

1500 = 500(1 + 0.015t)

1500 / 500 = 1 + 0.015t

3 = 1 + 0.015t

3 - 1= 0.015t

2 = 0.015t

2 / 0.015 = 0.015t / 0.015

133.333 = t

133.33 years

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Nina [5.8K]

Answer:

y=x+5

Step-by-step explanation:

y-y1=m(x-x1)

y=-x+2

slope of y=-x+2 is -1, perpendicular slope is 1

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A distance AB is observed repeatedly using the same equipment and procedures, and the results, in meters, are listed below: 67.4
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Answer:

a) \bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

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s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

Step-by-step explanation:

For this case we have the following dataset:

67.401, 67.400, 67.402, 67.396, 67.406, 67.401, 67.396, 67.401, 67.405, and 67.404

Part a: Determine the most probable value.

For this case the most probably value would be the sample mean given by this formula:

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And if we replace we got:

\bar X =\frac{67.401+67.400+67.402+67.396+67.406+67.401+67.396+67.401+67.405+67.404}{10}=67.401

Part b: Determine the standard deviation

The sample deviation is calculated from the following formula:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And for this case after replace the values and with the sample mean already calculated we got:

s=0.0036

If we assume that the data represent a population then the standard deviation would be given by:

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n}}

And then the deviation would be:

\sigma =0.00319

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