Answer:
Step-by-step explanation:
At first,
Let start writing the squares of number 0 to 10,
0²=0
1²=1
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
9²=81
10²=100
Now,
According to your question,
- The two numbers should be square numbers
- They should be greater than 1.
- Their sum should be 100.
Hence, your given conditions matches with the numbers 64 and 36.
Therefore, the numbers are 64 and 36.
- 64 and 36 are greater than 1.
- 64 is a square of 8 and 36 is the square of 6.
- 64+36=100
B :81 EXPLANATION
The angle with the greatest measure corresponds to the longest:
Since we know the three side lengths, we use the cosine rule to obtain;
{a}^{2} = {b}^{2} + {c}^{2} - 2bc \cos(A)
where a=21, b=18 and c=14
{21}^{2} = {18}^{2} + {14}^{2} - 2 \times 18 \times 14\cos(A)
44 1= 324+ 196 - 504\cos(A)
44 1= 520 - 504\cos(A)
44 1 - 520 = - 504\cos(A)
- 79 = - 504\cos(A)
\cos(A) = 0.1567
A = \cos ^{ - 1} (0.1567) = 80.98 \degree
1) total $ = 2543
2) x -> printer y-> computer z -> scanner
3) y = x + 1502
4) x = z + 123 -> x - 123 = z
5) 2543 = (x + 1502) + (x - 123) + x
6) 2543 = x + 1502 + x - 123 + x
7) 2543 = 3x + 1379
8) 2543 - 1379 = 3x
9) x = 388$
10) y = x + 1502
11) y = 1890$
computer costs 1890$
