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ehidna [41]
2 years ago
6

Find the surface area of the cone in terms of pi. 15cm 3cm

Mathematics
1 answer:
fgiga [73]2 years ago
3 0

Answer:

SA = 54π cm^2

A

Step-by-step explanation:

{\pi}rs + {\pi} {r}^{2}

radius = 3cm

slant height = 15 cm

follow the formula

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Nia's bag weighs 5-sixths of the maximum weight allowed for bags on an airplane. The maximum weight allowed is 45 pounds. What i
scZoUnD [109]

Answer:

54

Step-by-step explanation:

copy  dot flip 45/1 divided by 5/6

first copy dot flip so 45/1 then multiply and flip 5/6 so it looks like this

45/1 x 6/5= 270/5 then you need to see how many time 5 goes in 270 which is 54 and thats you anwser hope this helps sorry if im wrong

4 0
3 years ago
The function f(x)=−3x+2 is defined over the domain −1
DENIUS [597]

Answer:

Yes.

Step-by-step explanation:

f\left(x\right)=-3x+2

f\left(-1\right)=-3(-1)+2

y=f(-1)=5

The domain of this function is all Real numbers \:\left(-\infty \:,\:\infty \:\right)

\{x \in \mathbb{R}: -\infty \:

7 0
3 years ago
Okay I do not get questions like this ..
liberstina [14]
The answer is D cuz its a +ve parabola and symmetric to the x axis
8 0
3 years ago
The CEO of the Jen and Benny's ice cream company is concerned about the net weight of ice cream in their 50 ounce ice cream tubs
MissTica

Answer:

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

Step-by-step explanation:

Data given and notation  

\bar X=54.98 represent the sample mean

s=8.43 represent the sample deviation

n=26 sample size  

\mu_o =52 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 52, the system of hypothesis would be:  

Null hypothesis:\mu \leq 52  

Alternative hypothesis:\mu > 52  

Since we don't know the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{54.98-52}{\frac{8.43}{\sqrt{26}}}=1.8025  

P-value  

We need to find the degrees of freedom given by:

df = n-1= 26-1 = 25

Since is a right tailed test the p value would be:  

p_v =P(t_{25}>1.8025)=0.0418  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the average is higher than 52 at 5% of signficance.  

7 0
3 years ago
Read 2 more answers
Do you guys know the angle?
Paha777 [63]
90 degrees :).........
6 0
3 years ago
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