Question

At a small liberal arts college, students can register for one to six courses. Let be the number of courses taken in the fall by a randomly selected student from this college. In a typical fall semester, 6% take one course, 6% take two courses, 12% take three courses, 20% take four courses, 41% take five courses, and 15% take six courses. Suppose that a student earns three credits for each course taken. Let equal the number of credits a student would earn if they complete the course. Find the probability that a randomly selected student earns more than 18 credits. Give your answer to two decimal places.

Answer 1

According to the probability distribution, there is a 0% probability that a randomly selected student earns more than 18 credits.

• A student earns 3 credits per course.

Thus, the probability distribution for the number of credits earned is:

$P(X = 3) = 0.06$

$P(X = 6) = 0.06$

$P(X = 9) = 0.12$

$P(X = 12) = 0.2$

$P(X = 15) = 0.41$

$P(X = 18) = 0.15$

Since no person takes more than 6 courses, there is a 0% probability that a randomly selected student earns more than 18 credits.

A similar problem is given at brainly.com/question/25117113