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melisa1 [442]
3 years ago
12

Does anyone know how to do this?

Mathematics
1 answer:
timama [110]3 years ago
5 0

Answer:

A

Step-by-step explanation:

\dfrac{f(x)}{g(x)}=\dfrac{x+1}{x^{2}-x}\\f(x) = \dfrac{x+1}{x^{2}-x}*g(x)\\\\\dfrac{2}{x}*\dfrac{x^{2}-x}{x+1}=g(x)\\\\\\\dfrac{2}{x}*\dfrac{x(x-1)}{x+1}=g(x)\\\\\\\dfrac{2(x-1)}{x+1}=g(x)\\\\\

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