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kozerog [31]
2 years ago
15

Dean was flying his drone at an elevation of 307 feet. A strong gust of wind then caused it to drop 59 feet.

Mathematics
2 answers:
Brilliant_brown [7]2 years ago
8 0

Answer:

The elevation is 248 feet.

Step-by-step explanation:

You subtract 307-59.

Annette [7]2 years ago
3 0
Answer is 248

Because 307 feet subtracted by 59 feet is 248
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Elina [12.6K]

Answer:

First Equation is Right which is -56/8 = 7

Step-by-step explanation:

LHS = -56/8

=> -7

RHS = -7

So LHS = RHS

6 0
2 years ago
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Rewrite the expression $6j^2 - 4j 12$ in the form $c(j p)^2 q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$
solniwko [45]

Rewrite the expression  6j^2 - 4j + 12$ in the form $c(j + p)^2 + q$, where $c$, $p$, and $q$ are constants. What is $\frac{q}{p}$

The ratio of \frac{q}{p}  = - 34

How to solve such questions?

Such Questions can be easily solved just by some Algebraic manipulations and simplifications. We just try to make our expression in the form which question asks us. This is the best method to solve such questions as it will definitely lead us to correct answers. One such method is completing the square method.

Completing the square is a method that is used for converting a quadratic expression of the form ax^{2} + bx + c to the vertex form

a(x - h)^{2} + k. The most common application of completing the square is in solving a quadratic equation. This can be done by rearranging the expression obtained after completing the square: a(x + m)^{2} + n, such that the left side is a perfect square trinomial

$6j^2 - 4j +12$

=  $6(j^2 - \frac{2}{3} j )+12$

= $6(j^2 - \frac{2}{3} j  +  \frac{1}{9}  )+\frac{102}{9}                   (Completing Square method)

=6( j- \frac{1}{3} )^{2}  +  \frac{34}{3}

On comparing with the given equation we get

p = - \frac{1}{3}     and q = \frac{34}{3}

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Learn more about completing the square method here :

brainly.com/question/26107616

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7 0
2 years ago
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mixas84 [53]

Answer: 80 feet.


Step-by-step explanation:

1. As you can see in the figure, triangle ABC and the triangle DFG are similar.

2. The scale of factor of triangle ABC to triangle DFG is the following:

sf=\frac{20ft}{4ft}\\sf=5ft

3. Therefore, the lenght of the side DG of the trinagle DFG is:

DG=5*AC\\DG=5*7ft\\DG=35ft

4. The perimeter of the triangle DFG is:

P_{DFG}=20ft+25ft+35ft=80ft

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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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a = 28 / √2

4 0
3 years ago
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