The only point in the solution space is that of selection ...
C (1, 3)
Answer:
6 is the smallest number by which 600 should be multiplied to make it as a perfect square.
Answer:
h (x)=-16x^(2)+3x+35 =
x-intercept(s): (3+√224932,0),(3−√2249 32,0)
y-intercept(s): (0,35)
Answer:
57.14%
Step-by-step explanation:
So to get this answer I just had to find out what percent 16 was of 28. So 57.14% of the dogs are purebred.
Let's represent the two numbers by x and y. Then xy=60. The smaller number here is x=y-7.
Then (y-7)y=60, or y^2 - 7y - 60 = 0. Use the quadratic formula to (1) determine whether y has real values and (2) to determine those values if they are real:
discriminant = b^2 - 4ac; here the discriminant is (-7)^2 - 4(1)(-60) = 191. Because the discriminant is positive, this equation has two real, unequal roots, which are
-(-7) + sqrt(191)
y = -------------------------
-2(1)
and
-(-7) - sqrt(191)
y = ------------------------- = 3.41 (approximately)
-2(1)
Unfortunately, this doesn't make sense, since the LCM of two numbers is generally an integer.
Try thinking this way: If the LCM is 60, then xy = 60. What would happen if x=5 and y=12? Is xy = 60? Yes. Is 5 seven less than 12? Yes.
