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3 years ago

When a force is applied to an object the work done is:

Physics

1 answer:

Readme [11.4K]3 years ago

6 0

Answer:

Explanation: When a force is applied on an object, the work done is the product of the applied force and the displacement produced(distance moved) by the force...

Work=ForceXDisplacement

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S A voltage ΔV is applied to a series configuration of n resistors, each of resistance R. The circuit components are reconnected

Flura [38]

The power of is series combination is Vn^2 times that of a parallel combination.

For series combination :

Req = R + R + R + ............... n times = nR

I = Δv/nr

Power = (Δv/nr)^2 × nr = Δv^2/nr

For parallel combination

1/req = 1/R + 1/R + 1/R +................(n times) = n/R

Req = R/n

Power = Δv/(R/n) = nΔv^2/R

Ratio = Δv^2/nr/n·Δv^2/R = 1/n^2

Hence, power of is series combination is Vn^2 times that of a parallel.

Learn more about parallel combination here:

brainly.com/question/12400458

#SPJ4

3 0

2 years ago

A wave has a wavelength of 4.9 m and a velocity of 9.8 m/s. The medium through which this wave is traveling is then heated so th

garri49 [273]

Answer:

the wavelength is 9.8 meters

Explanation:

We can use the relationship:

Velocity = wavelenght*frequency.

Initially we have:

wavelenght = 4.9m

velocity = 9.8m/s

then:

9.8m/s = 4.9m*f

f = 9.8m/s/4.9m = 2*1/s

now, if the velocity is doubled and the frequency remains the same, we have:

2*9.8m/s = wavelenght*2*1/s

wavelenght = (2*9.8m/s)*(1/2)s = 9.8 m

6 0

3 years ago

Read 2 more answers

What is the difference between a partial and total lunar eclipse?

storchak [24]

Answer:

During a total lunar eclipse, the moon and sun are on the exact opposite sides of the Earth, leaving the moon entirely in the Earth's shadow. During a partial lunar eclipse, only part of the moon is in the Earth's shadow.

Explanation:

5 0

2 years ago

A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the

svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength is given by

$\lambda = \dfrac{2L}{n}$

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

$f = n\dfrac{v}{2L}$

now, wavelength calculation

n = 1

$\lambda_1 = \dfrac{2\times 2}{1}$

λ₁ = 4 m

n = 2

$\lambda_2 = \dfrac{2\times 2}{2}$

λ₂ = 2 m

n =3

$\lambda_3 = \dfrac{2\times 2}{3}$

λ₃ = 1.333 m

now, frequency calculation

n = 1

$f = n\dfrac{v}{2L}$

$f_1 =1\times \dfrac{50}{2\times 2}$

f₁ = 12.5 Hz

n = 2

$f = n\dfrac{v}{2L}$

$f_2 =2\times \dfrac{50}{2\times 2}$

f₂= 25 Hz

n = 3

$f = n\dfrac{v}{2L}$

$f_3 =3\times \dfrac{50}{2\times 2}$

f₃ = 37.5 Hz

8 0

3 years ago

Imagine you are standing in the antarctic during the southern hemisphere summer. the sky is clear and blue. there are no clouds

faltersainse [42]

Answer:

The shadow will appear dark

Explanation:

Your shadow is caused by your body blocking incident light rays from reach the ground under the shadow area. The absence of light means there will be no light reflected from the ground making it appear dark.

6 0

3 years ago