Throw it sideways and try to make it spin around but it needs to be thrown high up then it should kinda glide down
Image from a far away object formed by a concave mirror
I have no idea but this is my best guess as a sophomore in college
Complete question:
A college dormitory room measures 14 ft wide by 13 ft long by 6 ft high. Weight density of air is 0.07 lbs/ft3. What is the weight of air in it under normal conditions?
Answer:
the weight of the air is 76.44 lbs
Explanation:
Given;
dimension of the dormitory, = 14 ft by 13 ft by 6 ft
density of the air, = 0.07 lbs/ft³
The volume of the air in the dormitory room = 14 ft x 13 ft x 6 ft
= 1092 ft³
The weight of the air = density x volume
= 0.07 lbs/ft³ x 1092 ft³
= 76.44 lbs
Therefore, the weight of the air is 76.44 lbs
Answer:
As point B is located inside the copper block so net electric field at point B is j.
Explanation:
Consider the figure attached below. The net electric field at location B,that is inside the copper block is zero because when a conductor is charged or placed in an electric field of external charges, net charge lies on the surface of conductor and there is no electric field inside the conductor. As point B is located inside the copper block so net electric field at point B is zero as well direction of net electric field at point B is zero.
Answer:
The answer to your question is below
Explanation:
If Oxygen has an atomic number of 8, we can conclude that:
- If neutral, it has 8 protons and 8 electrons
- It has 8 neutrons and its atomic mass is 16 (A = 8 + 8)
- It must be located in the group VI A
- Its valence number must be 6
- Its Oxidation number is -2
