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3 years ago

A pendulum oscillates 12 times in 4 seconds. what is the length of the pendulum?

Physics

1 answer:

seraphim [82]3 years ago

6 0

Answer:

L = 2.8 cm

Explanation:

Period T = 4 / 12 = 1/3 s

T = 2π√(L/g)

L = (T/2π)²g

L = ((1/3)/2π)²9.8 = 0.02758... ≈ 2.8 cm

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Answer:

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Explanation:

Given that,

Speed of car = 34.0 m/s

Suppose The car race in the circle parallel to the ground surface is at an angle 40°

The radius of circular path $r = d\cos\theta$

Normal force acting on the car = N

We need to calculate the value of d

Using component of normal force

The horizontal component of normal force is equal to the gravitational force.

$N\cos\theta=mg$ ....(I)

The vertical component of normal force is equal to the centripetal force

$N\sin\theta=\dfrac{mv^2}{r}$ .....(II)

Divided equation (I) by equation (II)

$\tan\theta=\dfrac{v^2}{gr}$

Put the value of g

$\tan\theta=\dfrac{v^2}{g\times d\cos\theta}$

$v^2=\tan\theta\times g\times d\cos\theta$

$v^2=g\times d\sin\theta$

$d=\dfrac{v^2}{g\sin\theta}$

Put the value into the formula

$d=\dfrac{(34.0)^2}{9.8\times\sin40}$

$d=183.51\ m$

Hence, The value of d is 183.51 m.

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