Answer: Angel observes a marble travel along a horizontal path at a constant rate. The marble travel 2/3 of the length- of the path in 50 seconds. At that rate, how many seconds does it take the object to travel the full length?
Step-by-step explanation: First, reason down from 2/3 to 1/3. Enter all values as fractions (proper or improper) or whole numbers. You will need to convert mixed numbers to improper fractions.
Hi there,
θ = 180º + the angle of the right-angled triangle.
For finding the angle we know that the opposite side measures 6 units and the adjacent side measures 8 units. So, the hypotenuse is 10 units.
If we want to find the angle of the right-angled triangle we have to use the following equation.
sin(the angle of the right-angled triangle) = ![\frac{6}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D)
⇒ the angle of the right-angled triangle =
≈ 36,87º
So,
θ = 180º + the angle of the right-angled triangle
θ ≈ 180º + 36,87º
θ ≈ 216,87º
sin(θ) = sin(216,87º)
sin(θ) =
sin(θ) = ![\frac{-3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B-3%7D%7B5%7D)
If you want to do it using properties:
θ = 180º + |the angle of the right-angled triangle|
⇒ sin(θ) = sin(180º + |the angle of the right-angled triangle|)
Using properties:
⇒ sin(θ) = sin(180º)*cos( |the angle of the right-angled triangle|) + cos(180º)*sin(|the angle of the right-angled triangle|)
Sin (180) = 0
⇒ sin(θ) = cos(180º)*sin(|the angle of the right-angled triangle|)
sin(the angle of the right-angled triangle) = -![\frac{6}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D)
And cos(180º) = -1
⇒ sin(θ) = -1* ![\frac{6}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B10%7D)
⇒ sin(θ) =
⇒ sin(θ) = ![\frac{-3}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B-3%7D%7B5%7D)
Answer:
y = 10x
Step-by-step explanation:
(2, 20)
(5, 50)
(7, 70)
From 2 to 5 we add 3 (x section)
From 20 to 50 we add 30 (y section)
We can do y/x = 30/3 = 10
The slope will be 10.
Hope this helped!
Have a supercalifragilisitcexpialidocious day!
Answer: − 18 x= 72
Step-by-step explanation:
Answer:
![\frac{x - 5}{x+1}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%20-%205%7D%7Bx%2B1%7D)
Step-by-step explanation:
![\mathrm{Factor}\:x^2+4x-45:\quad \left(x-5\right)\left(x+9\right)\\=\frac{\left(x-5\right)\left(x+9\right)}{x^2+10x+9}\\\mathrm{Factor}\:x^2+10x+9:\quad \left(x+1\right)\left(x+9\right)\\=\frac{\left(x-5\right)\left(x+9\right)}{\left(x+1\right)\left(x+9\right)}\\\mathrm{Cancel\:the\:common\:factor:}\:x+9\\=\frac{x-5}{x+1}](https://tex.z-dn.net/?f=%5Cmathrm%7BFactor%7D%5C%3Ax%5E2%2B4x-45%3A%5Cquad%20%5Cleft%28x-5%5Cright%29%5Cleft%28x%2B9%5Cright%29%5C%5C%3D%5Cfrac%7B%5Cleft%28x-5%5Cright%29%5Cleft%28x%2B9%5Cright%29%7D%7Bx%5E2%2B10x%2B9%7D%5C%5C%5Cmathrm%7BFactor%7D%5C%3Ax%5E2%2B10x%2B9%3A%5Cquad%20%5Cleft%28x%2B1%5Cright%29%5Cleft%28x%2B9%5Cright%29%5C%5C%3D%5Cfrac%7B%5Cleft%28x-5%5Cright%29%5Cleft%28x%2B9%5Cright%29%7D%7B%5Cleft%28x%2B1%5Cright%29%5Cleft%28x%2B9%5Cright%29%7D%5C%5C%5Cmathrm%7BCancel%5C%3Athe%5C%3Acommon%5C%3Afactor%3A%7D%5C%3Ax%2B9%5C%5C%3D%5Cfrac%7Bx-5%7D%7Bx%2B1%7D)
Hello Fellow Army!~