A landscaping company uses a mixture of 20 pounds of grass seed and 356 pounds of fertilizer when reseeding a customer's lawn.

Mathematics

1 answer:

stealth61 [152]2 years ago

7 0

Answer:

Step-by-step explanation:

for 20 pounds of grass seed, we need 356 pounds of fertilizer

20 pounds of grass seed : 356 pounds of fertilizer

divide both sides by 20 to get 1 pound of grass seed on one side, as we want to figure out the corresponding amount of fertilizer for 1 pound of grass seed

20 pounds of grass seed/20 : 356 pounds of fertilizer/20

1 pound of grass seed: 17.8 pounds of fertilizer

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Find the point P on the line y=2x that is closest to the point (20,0) .what is the least distance between pans (20,0)?

Vsevolod [243]

The closest point on a line, to another point, will be a point that's on a normal of that line, or a line that is perpendicular to it, notice picture below

so, y = 2x, has a slope of 2, a perpendicular line to it, will have a slope of negative reciprocal that, or $\bf 2\qquad negative\implies -2\qquad reciprocal\implies \cfrac{1}{-2}\implies -\cfrac{1}{2}$

so, we know that line passes through the point 20,0, and has a slope of -1/2

if we plug that in the point-slope form, we get $\bf y-0=-\cfrac{1}{2}(x-20)\implies y=-\cfrac{1}{2}x+10$

now, the point that's on 2x and is also on that perpendicular line, is the closest to 20,0 from 2x, thus, is where both graphs intersect, as you can see in the graph

thus $\bf 2x=-\cfrac{1}{2}x+10$ solve for "x'

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not sure on the 2nd part, but sounds like, what's the distance from that point to 20,0, well, if that's the case, just use the distance equation

$\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ \square }}\quad ,&{{ \square }})\quad 
% (c,d)
&({{ \square }}\quad ,&{{ \square }})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}$