Answer:
The experimental probability that terry will win their next game is 
Step-by-step explanation:
While theoretical probability is the ratio of the number of favourable outcomes to the total number of outcomes, the experimental probability is the ratio of number of times the event is occurring to the total number of trials of the experiment.
Out of 5 games jay wins 3
Now the experimental probability that terry will win their next game
= 1 - Probability of Jay winning the game----------------------(1)
Probability of Jay winning the game = 
=> 
----------------------------------------------------(2)
Substituting (2) in (1)
=> 1 -
=> 
=>
Answer:
<h2><u><em>
D</em></u></h2>
Step-by-step explanation:
You can first reduce this fraction by dividing both the numerator and denominator by the Greatest Common Factor of 549 and 999. I know that
61/111
is the same as
61÷111
Then using
Long Division for 61 divided by 111
and rounding to a Max of 4 Decimal Places gives me
=0.5495/.5495
<h3>then move the decimal point a digit to the <u><em>
RIGHT!!!!</em></u></h3>
I say that answer would be C:
2 years of lost wages
(45K+45K) = 90K
TOTAL cost of school = 30K
sum of investment
(90K+30K) = 120K
5 years to recover investment
(120K/5yrs) = 24K per year
Salary plus amount required to recover investment
<span>(24K+45K) = 69K
I hope my answer has come to your help. God bless and have a nice day ahead!</span>
You have the following expressions given in the problem above:
(y^2/y-3)(y^2-y-6/y^2+y)
By applying the exponents properties, you can simplify it, as it shown below:
(y^2/y-3)(y^2-y-6/y^2+y)
(y^4-y^3-6y^2)/(y^3+y^2-3y2-3y)
(y^4-y^3-6y^2)/(y^3-2y2-3y)
Then, you have:
y^2(y^2-y-6)/y(y^2-2y-3)
(y^2-y-6)/(y^2-2y-3)
The answer is: (y^2-y-6)/(y^2-2y-3)
Step-by-step explanation:
a)
well, logically, it must be M, 2
b)
this is a combined probability for one single pair of possible outcomes.
there are 15 pairs, all with the same probability.
so, P(Q, 4) = number of desired outcomes / number of possible outcomes = 1/15
as combined probability we can also say the probability to get 4 on one wheel is 1/5, and the probabilty to get Q on the other wheel is 1/3
so, P(Q, 4) = 1/3 × 1/5 = 1/15
