12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
Answer: 9 over 10
Step-by-step explanation:
You can turn 5 into 10/2 and add to x/2
then you need to use simple algebra to left the x alone in the equation so you need to multiply both sides by 2 so you get
2y=10+x
then you need to subtract both sides a 10 so
2y-10=x
now change the x to f'(x) and y to x so:
f'(x)=2x-10
A
B
Just search it up on a math website or sum
