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Neko [114]
2 years ago
14

10 points to you if you help me and brainlyist

Mathematics
1 answer:
Kazeer [188]2 years ago
3 0

Answer:

Step-by-step explanation:

For the frequency distribution, count the numbers that satisfy each category.

79 to 83: 4 (81, 82, 83, 81)

84 to 88: 3 (87, 88, 86)

89 to 93: 7 (92, 93, 93, 93, 90, 90, 91)

94 to 98: 1 (97)

For the historagram, raise the bars at the bottom of the histogram to the numbers above (4, 3, 7, 1; in this order)

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Explain how you know that the equation 3x = 9 is equivalent to the equation x =3.
Marat540 [252]

Hey there!

If x = 3 then substitute it into the equation

3(3) = 9

3(3) = 9

9 = 9

Answer: 9 = 9, so this makes this statement is true

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

6 0
3 years ago
a five question multiple choice quiz has five choices for each answer. use the random number table provided, with 0's representi
Montano1993 [528]

The experimental probability of correctly guessing at random exactly zero correct answers is (4/5)⁵

<h3>What is Probability?</h3>

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

Here, total multiple choice quiz = 5 questions

          Each question contains 5 choices in which 1 choice is correct and remaining 4 are incorrect.

Possibility of first wrong choice = 4/5

Possibility of second wrong choice = 4/5

Possibility of third wrong choice = 4/5

Possibility of fourth wrong choice = 4/5

Possibility of fifth wrong choice = 4/5

Overall probability for Zero correct answer=(4X4X4X4X4)/(5X5X5X5X5)

                                                                        = (4/5)⁵

Thus, the experimental probability of correctly guessing at random exactly zero correct answers is (4/5)⁵

Learn more about Probability from:

brainly.com/question/11234923

#SPJ1

4 0
2 years ago
Convert the time. Enter your answer in the box.<br><br> 4 minutes 53 seconds = <br> seconds
Vsevolod [243]
293 seconds ____________
3 0
3 years ago
write a function g whose graph represents a translation 2 units to the right followed by a horizontal stretch by a factor or 2 o
Alenkinab [10]
\bf f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}&#10;\\ \quad \\&#10;f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}\\\\&#10;f(x)=&{{  A}} \left|{{ B }}x+{{  C}}  \right|+{{  D}}&#10;\\\\&#10;--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\&#10;\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the x-axis}&#10;\\\\&#10;\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\&#10;\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\&#10;\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\&#10;\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\&#10;\bullet \textit{ vertical shift by }{{  D}}\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\&#10;\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\&#10;\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

with that template in mind, let's see,
 
\bf f(x)=|x| \implies \begin{array}{lllccll}&#10;f(x)=&1|&1x&+0|&+0\\&#10;&\uparrow &\uparrow &\uparrow &\uparrow \\&#10;&A&B&C&D&#10;\end{array}

so, to shift it to the right by 2 units, simply set C = 2.
to stretch it by 2, set A = 1/2.

the smaller A is, the wider it opens, the larger it is, the more it shrinks.
5 0
3 years ago
Kade has 100 flag pins. He has 221 frog pins and 10 dinosaur pins. How many flag and frog pins does Kade have?
bazaltina [42]

Answer:

321

Step-by-step explanation:

because  100+221 equals 321

Hope this helped.

5 0
3 years ago
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