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kobusy [5.1K]
3 years ago
14

Which expression is equivalent to 6⋅6⋅6? 36 6³ 66

Mathematics
2 answers:
devlian [24]3 years ago
5 0

Answer:

6^3

Step-by-step explanation:

6^3 is the same as 6*6*6

MaRussiya [10]3 years ago
5 0

Answer:

6^3

Step-by-step explanation:

6 x 6 x 6 is the same as 6 to the 3rd power.

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Jordan starts his day by doing his exercises. Jordan jumps rope for 10 minutes and lifts weights for 30 minutes. Jordan runs 10
romanna [79]

Answer:

35

Step-by-step explanation:

0.25 x 140 = 35

8 0
3 years ago
Joey is buying plants for his garden. He wants to have at least twice as many flowering plants as nonflowering plants and a mini
vodomira [7]
(24, 12) and (36, 0).  The least amount of flowering plants occurs when x=2y, and the largest amount occurs when y=0.  These two points satisfy both conditions and both sum to 36.
7 0
3 years ago
Read 2 more answers
In ⊙P, QR≅ST. Which statement must be true? Select all that apply.
den301095 [7]

The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π

<h3>The circle with center P</h3>

Given that the circle has a center P

It means that lengths PQ, PR, PS and PT

From the question, we understand that QR = ST.

This implies that triangles QRP and STP are congruent.

i.e.  △QRP ≅ △STP is true

<h3>The length of the minor arc</h3>

The given parameters are:

Angle, Ф = 99

Radius, r = 1

The length of the arc is:

L = Ф/360 * 2πr

So, we have:

L = 99/360 * 2π * 1

Evaluate

L = 198/360π

Divide

L = 11/20π

Hence, the length of the minor arc is 11/20π

Read more about circle and arcs at:

brainly.com/question/3652658

#SPJ1

5 0
2 years ago
Write an equation to represent m varies inversely as the square of q ?​
kolezko [41]

Answer:

m = \frac{k}{q^2}

Step-by-step explanation:

Given m varies inversely as q² then the equation relating them is

m = \frac{k}{q^2} ← k is the constant of variation

4 0
3 years ago
Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)
Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

x^{2} +y^{2}+4x-1=0

Step-by-step explanation:

<u>Explanation:</u>-

<u>Step 1:</u>-

The equation of the circle having center and radius is

(x-h)^2+(y-k)^2=r^2

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

      (\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2}  )

    (-2,0)

therefore center (h,k) = (-2,0)

<u>Step 2:-</u>

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}

r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}

r=\sqrt{5}

<u>Step 3</u>:-

center (h,k) = (-2,0) and

radius r=\sqrt{5}

The standard form of circle equation

(x-h)^2+(y-k)^2=r^2

(x-(-2))^2+(y-0)^2=\sqrt{5} ^2

on simplification is

x^{2} +y^{2}+4 x-1=0

5 0
3 years ago
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