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Novosadov [1.4K]
2 years ago
8

Please help me plss! PLS​

Computers and Technology
2 answers:
konstantin123 [22]2 years ago
4 0

Answer:

1.  Formula is A2 : A9 = COUNT( A2: A9 ) = 8

2. Formula is SUM( A2: A9 ) = 36

3. Formula is B2 : B9 = COUNT( B2: B9) = 8

4. Formula is  MAX( C2: C9) = 5

5. Formula is MIN( C4: C8) = 3

6. Formula is SUM( C5 - C6) = 0

7. Formula is AVERAGE( C2: C9) = 4

Explanation: Have a nice day! ✌️

lukranit [14]2 years ago
3 0

Explanation:

OKAY, you got your asnswer.. sorry I could not help.

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#include<iostream>

using namespace std;

/*C++ Function to print leaders in an array */

void printLeaders(int arr[], int size)

{

  for (int i = 0; i < size; i++)

   {

       int j;

       for (j = i+1; j < size; j++)

       {

           if (arr[i] <=arr[j])

               break;

       }  

       if (j == size) // the loop didn't break

           cout << arr[i] << " ";

 }

}

/* Driver program to test above function */

int main()

{

   int arr[] = {16, 17, 4, 3, 5, 2};

   int n = sizeof(arr)/sizeof(arr[0]);

   printLeaders(arr, n);

   return 0;

}

Learn more about Development here-

brainly.com/question/28011228

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7 0
1 year ago
What is 1/10 of 2.0 in decimal form​
son4ous [18]

Answer to this is .2

5 0
3 years ago
Different algorithms can be made to complete the same task in different ways.
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True hope this helps you and everyone!

7 0
3 years ago
Read 2 more answers
Description
lapo4ka [179]

Answer:

from datetime import time, datetime, timedelta, date

for _ in iter(list, 0):

   t1 = input("Please enter time one: ")

   t2 = input("Please enter time two: ")

   if t1.isdigit() == True and (int(t1[:2])<=23 and int(t1[2:]) <= 59)\

       and t2.isdigit() == True and (int(t2[:2])<= 23 and int(t2[2:])<=59):

       time_1 = time(hour=int(t1[:2]), minute=int(t1[2:]))

       time_2 = time(hour= int(t2[:2]), minute=int(t2[2:]))

       if time_1 > time_2:

           diff = datetime. combine (date. today( ), time_1) - datetime. combine(date. today ( ), time_2)

       else:

           diff = datetime. combine (date. today( ), time_2) -datetime. combine(date. today ( ), time_1)

       diff_list = str(diff).split(":")

       del diff_list[2]

       diff_t = "". join (diff_list)

       print(diff_t)

       break        

   if t1.isdigit() == False or t2.isdigit() == False:

       print("Military Time Forest Required: Bad input, try again.")

       continue

   elif int(t1[:2])> 23 or int(t2[:2])> 23:

       print("Military Tine Format Required: Hours must be between 00 and 23, try again")

       continue

   elif int(t1[2:])> 59 or int(t2[2:])> 59:

       print("Military Tine Format Required: Minutes must be between me and 59, try again")

       continue

Explanation:

The python Datetime package is used to manipulate date and time, creating immutable Datetime objects from the various python data types like integer and string. The block of code above is a conditional for-loop statement that gets two user time value inputs and prints out the difference as a string in Military forest time format.

5 0
3 years ago
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