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2 years ago

5

g Assume that this program is run on a processor with data cache of size big enough that the entire array arr can fit in the cac

he. (a) How many paths does the function foo of this program have

Computers and Technology

1 answer:

Dimas [21]2 years ago

7 0

Answer:

A. 2

Explanation:

The food function in the C source code uses two for loop statements to fill and array of size 100 with 100 values ranging from 1 to 100 and the second to get the total sum to the values in the array. With this, two program paths are created.

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Create the SQL statements for displaying the results for each of the following scenarios in the Academic Database. Save these st

Whitepunk [10]

Answer:

CREATE FUNCTION exam_eligible_students

RETURN NUMBER AS

num_students NUMBER(15);

BEGIN

SELECT COUNT(STUDENT_ID)

INTO num_students

FROM STUDENT_ATTENDANCE

WHERE ELIGIBILITY_FOR_EXAMS = 'Y';

RETURN (num_students);

END;

Explanation:

exam_eligible_students is a made of name for the FUNCTION to be called.

num_students is a made up name for the RETURN to be called. The RETURN name is referenced in the INTO statement and as the name of the the return in the RETURN line in ().

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3 years ago

Find the inverse function of f(x)= 1+squareroot of 1+2x

Svetllana [295]

Answer:

Therefore the inverse function of $f(x)=1+\sqrt{1+2x}$ is $\frac{x^2-2x}{2}$

Explanation:

We need to find the inverse of function $f(x)=1+\sqrt{1+2x}$

Function Inverse definition :

$\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}$

$y=1+\sqrt{1+2x}$ $\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y$

$x=1+\sqrt{1+2y}$

$\mathrm{Solve}\:x=1+\sqrt{1+2y}\:\mathrm{for}\:y$

$\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}$

$1+\sqrt{1+2y}-1=x-1$

Simplify

$\sqrt{1+2y}=x-1$

$\mathrm{Square\:both\:sides}$

$\left(\sqrt{1+2y}\right)^2=\left(x-1\right)^2$

$\mathrm{Expand\:}\left(\sqrt{1+2y}\right)^2:\quad 1+2y$

$\mathrm{Expand\:}\left(x-1\right)^2:\quad x^2-2x+1$

$1+2y=x^2-2x+1$

$\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}$

$1+2y-1=x^2-2x+1-1$

$\mathrm{Simplify}$

$2y=x^2-2x$

$\mathrm{Divide\:both\:sides\:by\:}2$

$\frac{2y}{2}=\frac{x^2}{2}-\frac{2x}{2}$

$\mathrm{Simplify}$

$y=\frac{x^2-2x}{2}$

Therefore the inverse function of $f(x)=1+\sqrt{1+2x}$ is $\frac{x^2-2x}{2}$

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