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Nastasia [14]
2 years ago
8

What is the equation of the line shown in this graph?

Mathematics
1 answer:
slava [35]2 years ago
5 0

Answer:

kailangan ko lng po ng points

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Please help ASAP I hate maths and am so confused
sveta [45]

Answer:

90 i think im sorry if its wrong

Step-by-step explanation:

5 0
2 years ago
Will mark brainiest!!<br> Only answer questions a and b
k0ka [10]

Answer:

f1 ( x ) valid pdf . f2 ( x ) is invalid pdf

k = 1 / 18 , i ) 0.6133 , ii ) 0.84792

Step-by-step explanation:

Solution:-

A) The two pdfs ( f1 ( x ) and f2 ( x ) ) are given as follows:

                     

- To check the legitimacy of a continuous probability density function the area under the curve over the domain must be equal to 1. In other words the following:

                   

- We will perform integration of each given pdf as follows:

                   

                   

Answer: f1 ( x ) is a valid pdf; however, f2 ( x ) is not a valid pdf.

B)

- A random variable ( X ) denotes the resistance of a randomly chosen resistor, and the pdf is given as follows:

                       if  8 ≤ x ≤ 10

                               0  otherwise.

- To determine the value of ( k ) we will impose the condition of validity of a probability function as follows:

                     

- Evaluate the integral as follows:

                     ... Answer

- To determine the CDF of the given probability distribution we will integrate the pdf from the initial point ( 8 ) to a respective value ( x ) as follows:

                     

To determine the probability p ( 8.6 ≤ x ≤ 9.8 ) we will utilize the cdf as follows:

                   p ( 8.6 ≤ x ≤ 9.8 ) = F ( 9.8 ) - F ( 8.6 )

                   p ( 8.6 ≤ x ≤ 9.8 ) =

ii) To determine the conditional probability we will utilize the basic formula as follows:

               p ( x ≤ 9.8  | x ≥ 8.6 ) = p ( 8.6 ≤ x ≤ 9.8 ) / p ( x ≥ 8.6 )

               p ( x ≤ 9.8  | x ≥ 8.6 ) = 0.61333 / [ 1 - p ( x ≤ 8.6 ) ]

               p ( x ≤ 9.8  | x ≥ 8.6 ) = 0.61333 / [ 1 - 0.27666 ]

               p ( x ≤ 9.8  | x ≥ 8.6 ) = 0.61333 / [ 0.72333 ]

               p ( x ≤ 9.8  | x ≥ 8.6 ) = 0.84792 ... answer

Hope it helps! ;)

4 0
2 years ago
Please help with math
padilas [110]
Algebra<span><span>Introduction to Algebra
</span>Variables<span> 
</span>Expressions<span> 
</span>Equations<span> 
</span>Solution of an equation<span> 
</span>Simplifying equations<span> 
</span>Combining like terms<span> 
</span>Simplifying with addition and subtraction<span> 
</span>Simplifying by multiplication<span> 
</span>Simplifying by division<span> 
</span>Word problems as equations<span> 
</span>Sequences VariablesA variable is a symbol that represents a number. Usually we use letters such as n, t, or x for variables. For example, we might say that s stands for the side-length of a square. We now treat s as if it were a number we could use. The perimeter of the square is given by 4 × s. The area of the square is given by s× s. When working with variables, it can be helpful to use a letter that will remind you of what the variable stands for: let n be the number of people in a movie theater; let t be the time it takes to travel somewhere; let d be the distance from my house to the park. ExpressionsAn expression is a mathematical statement that may use numbers, variables, or both.Example:The following are examples of expressions:2x3 + 72 × y + 52 + 6 × (4 - 2)z + 3 × (8 - z<span>)</span></span>
4 0
3 years ago
You are building a rectangular dog pen with the length is twice as long as the width. You have 120 feet of fencing what are the
Yakvenalex [24]

Answer:

Dimensions are 20 + 20 + 40 + 40

Step-by-step explanation:

3 0
3 years ago
∠EFG and ∠GFH are a linear​ pair, m∠EFG=3n+19, and m∠GFH=55+33 What are m∠EFG and m∠​GFH?
romanna [79]
A linear pair is a pair of angles that form a straight line and are therefore, equal to 180 degrees

3n + 19 + 55 + 33 = 180
3n + 107 = 180
3n = 180 - 107
3n = 73
n = 73/3 


so < EFG = 3n + 19 = 3(73/3) + 19 = 73 + 19 = 92
and < GFH = 55 + 33 = 88
5 0
3 years ago
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