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2 years ago

Please help it for my math test tomorrow helpppp

Mathematics

1 answer:

loris [4]2 years ago

7 0

15: M= 2
B= -5
Slope intercept form= y=2x-5

16: y=5/8x + 1/2

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2 years ago

HELP!!!

Naddika [18.5K]

Check the picture below, so it reaches the maximum height at the vertex, let's check where that is

$h(t)=64t-16t^2+0 \\\\[-0.35em] ~\dotfill\\\\ \textit{vertex of a vertical parabola, using coefficients} \\\\ h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+64}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right) \\\\\\ \left(-\cfrac{ 64}{2(-16)}~~~~ ,~~~~ 0-\cfrac{ (64)^2}{4(-16)}\right)\implies \stackrel{maximum~height}{(2~~,~~\stackrel{\downarrow }{64})}$

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