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solniwko [45]
3 years ago
6

Super simple, just don't know if I am right or not.

Mathematics
1 answer:
Rzqust [24]3 years ago
4 0
The answer is 100% true
When it is graphed it points up over x axis
See pic

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Please help thank you!
Verizon [17]

Answer:

18/(10-7)+2=8

(48/2)-4^2 +2*2=12

I hope you have a nice day!

3 0
3 years ago
Write a polynomial as the sum of the monomials and write it in standard form. For each of the above specify the degree of the re
klio [65]

Answer:

2b³ +2a -2c . . . . degree 3 polynomial

Step-by-step explanation:

The monomials are ...

... 4a . . . . degree 1 in a

... -5b·b² = -5b³ . . . . degree 3 in b

... -3c . . . . degree 1 in c

... 7b³ . . . . degee 3 in b (like term with -5b³)

... +c . . . . degree 1 in c (like term with -3c)

... -2a . . . . degree 1 in a (like term with 4a)

So, we have 3 pairs of like terms. The like terms can be combined by summing their coefficients.

The degree of the polynomial is that of the highest-degree term. (Here, the b³ term makes it a polynomial of degree 3.)

... 4a -2a = (4-2)a = 2a . . . . combining the "a" terms

... -5b³ +7b³ = (-5+7)b³ = 2b³ . . . . combining the b³ terms

... -3c +c = (-3 +1)c = -2c . . . . combining the "c" terms

In standard form, we write the highest-degree term first. Follwing terms are in order by decreasing degree. It is convenient, but perhaps not required, to then write the terms of the same degree in alphabetical order.

... = 2b³ +2a -2c . . . . a 3rd degree polynomial

7 0
3 years ago
A vehicle traveled at a speed of 54 kilometers per hour for 3 hours. find the distance traveled
skad [1K]

Answer:

162

Step-by-step explanation:

54x3

7 0
3 years ago
Use the equation y=-3x if the x-value is 2 1/3
disa [49]

Answer:

y=-7

Step-by-step explanation:

Multiply -3 times 2 1/3

Hope this helps!

5 0
3 years ago
Read 2 more answers
The box plots show the high temperatures in June and August for Denver in degrees Fahrenheit.
Kryger [21]

Hi There!

---------------------------------------------------------

Full Question:

The box plots show the high temperatures in June and August for Denver in degrees Fahrenheit.

Which can you tell about the mean temperatures for these two months?

There is not enough information to determine the mean temperatures.

The mean temperature for August is higher than June's mean temperature.

The mean temperature for June is equal to the mean temperature for August.

The high interquartile range for August pulls the mean temperature above June's mean temperature.

---------------------------------------------------------

Interquartile Range Formula: Q3 - Q1

Interquartile Range for August: 10

Interquartile Range for June: 8

---------------------------------------------------------

Median = Mean

June: 82

August: 82

---------------------------------------------------------

Answer: The mean temperature for June is equal to the mean temperature for August.

---------------------------------------------------------

Hope This Helps :)

5 0
3 years ago
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