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timurjin [86]
3 years ago
8

Find the percent decrease. Round to the nearest percent. From 96°F to 71°F​

Mathematics
1 answer:
barxatty [35]3 years ago
7 0

Step-by-step explanation:

100% = 96

1% = 100%/100 = 96/100 = 0.96

the temperature changed by 96 - 71 = 25.

how many % are these 25 ?

we check how often 1% fits into 25.

that is done by division :

25 / 0.96 = 26.04166667 ≈ 26%

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Find the value of B.<br> 200 + 50 + B = 100 + 47 + 10 + 100
larisa86 [58]

Answer:

The value of B is 7.

B = 7

3 0
3 years ago
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Giving twenty points! (: (10 points each!)
mrs_skeptik [129]
A. given
b. distributive property (a(b+c)=ab+ac)
c. addition or commutative property (a+b=b+a)
d. subtraction property of equality (if a=b, then a-c=b-c)
e. division property of equality (if a=b, then a/c=b/c)
f. equality property (if a=b, then b=a)
4 0
3 years ago
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in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

3 0
3 years ago
Solvex + 5-6 = 7.
yKpoI14uk [10]
I got x=8
Because 5-6=-1….. 7- -1= 8…… then it’s just that.I



I don’t understand the answers given tho but that’s my guess
8 0
2 years ago
Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (
Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

P(\frac{T}{S}) = 0.95

P(\frac{T}{S^c}) = 0.05

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

P(S^c) =  1 - P(S)

= 1 - 0.3

= 0.7

ii. P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}

= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }

= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}

= 0.8906

iii. P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}

= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }

= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}

= 0.0221

We simply applied the above formulas so that the each part could come

8 0
3 years ago
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