If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
Answer:
x = π/3, x = 5π/3, x = 4π/3
Step-by-step explanation:
Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3 = 0.
![2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}](https://tex.z-dn.net/?f=2%5Ccos%20%5Cleft%28x%5Cright%29-1%3D0%2C%5C%5C2%5Ccos%20%5Cleft%28x%5Cright%29%3D1%2C%5C%5C%5Ccos%20%5Cleft%28x%5Cright%29%3D%5Cfrac%7B1%7D%7B2%7D)
Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.
Similarly:
![\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}](https://tex.z-dn.net/?f=%5C%3A2%5Csin%20%5Cleft%28x%5Cright%29%2B%5Csqrt%7B3%7D%3D0%2C%5C%5C2%5Csin%20%5Cleft%28x%5Cright%29%3D-%5Csqrt%7B3%7D%2C%5C%5C%5Csin%20%5Cleft%28x%5Cright%29%3D-%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D)
The general solutions for sin(x) = - √3/2 are x = 4π/3 + 2πn and x = 5π/3 + 2πn. Therefore x = 4π/3 and x = 5π/3 in this case.
So we have x = π/3, x = 5π/3, and x = 4π/3 as our solutions.
Number of containers for 2 litres of water = 1
So, number of containers for 1 litre of water = ½
So, number of containers for 30 litres of water
= ½ × 30
= 30/2
= 15
So, 15 of these containers would be needed to fill a 30-liter drum.
Answer:
If the dimension increased by doubled, tripled or quadrupled, then it will be 2x, 3x, or 4x for each dimension.
You have to multiply whats outside the parenthesis with everything that is inside, so
![x^{-3}y^0.(x^2-3x^5y^4)](https://tex.z-dn.net/?f=x%5E%7B-3%7Dy%5E0.%28x%5E2-3x%5E5y%5E4%29)
![x^{-3}y^0.x^2-x^{-3}y^0.3x^5y^4](https://tex.z-dn.net/?f=x%5E%7B-3%7Dy%5E0.x%5E2-x%5E%7B-3%7Dy%5E0.3x%5E5y%5E4)
Multiplication of same bases we sum the exponents
![x^{-3+2}y^0-3x^{-3+5}y^{0+4}](https://tex.z-dn.net/?f=x%5E%7B-3%2B2%7Dy%5E0-3x%5E%7B-3%2B5%7Dy%5E%7B0%2B4%7D)
![x^{-1}.1-3x^2y^4](https://tex.z-dn.net/?f=x%5E%7B-1%7D.1-3x%5E2y%5E4)
![x^{-1}-3x^2y^4](https://tex.z-dn.net/?f=x%5E%7B-1%7D-3x%5E2y%5E4)
Alternative B.