The point (19, -4) is in quadrant 4. I hoped this helped!
Answer: There is no polygon with the sum of the measures of the interior angles of a polygon is 1920°.
Step-by-step explanation:
The sum of the measures of interior angles of a polygon with
sides is given by:-
![(n-2)\times180^{\circ}](https://tex.z-dn.net/?f=%28n-2%29%5Ctimes180%5E%7B%5Ccirc%7D)
Given: The sum of the measures of the interior angles of a polygon is 1920°.
i.e. ![(n-2)\times180^{\circ}=1920^{\circ}](https://tex.z-dn.net/?f=%28n-2%29%5Ctimes180%5E%7B%5Ccirc%7D%3D1920%5E%7B%5Ccirc%7D)
![n-2=\dfrac{1920}{180}\\\\ n= \dfrac{1920}{180}+2\\\\ n=\dfrac{2280}{180}=12.67](https://tex.z-dn.net/?f=n-2%3D%5Cdfrac%7B1920%7D%7B180%7D%5C%5C%5C%5C%20n%3D%20%5Cdfrac%7B1920%7D%7B180%7D%2B2%5C%5C%5C%5C%20n%3D%5Cdfrac%7B2280%7D%7B180%7D%3D12.67)
But number of sides cannot be in decimal.
Hence, there is no polygon with the sum of the measures of the interior angles of a polygon is 1920°.
Answer:
or ![4\sqrt{5}](https://tex.z-dn.net/?f=4%5Csqrt%7B5%7D)
Step-by-step explanation:
Using the distance formula:
![d=\sqrt{(7-(-1))^2+(6-2)^2}=\sqrt{8^2+4^2}=\sqrt{64+16}=\sqrt{80}=4\sqrt{5}](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%287-%28-1%29%29%5E2%2B%286-2%29%5E2%7D%3D%5Csqrt%7B8%5E2%2B4%5E2%7D%3D%5Csqrt%7B64%2B16%7D%3D%5Csqrt%7B80%7D%3D4%5Csqrt%7B5%7D)
Hope this helps!
Answer: 20.48
Step-by-step explanation:
use the pythagorean theorem for the diagnal sides
3^2+3^2=c^2
9+9=c^2
18=c^2
![\sqrt{18}](https://tex.z-dn.net/?f=%5Csqrt%7B18%7D)
this gives you 4.24
now add 6+6+4.24+4.24 to get 20.48