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Vesnalui [34]
3 years ago
12

Denise, Keith and Tim live in the same neighborhood. Denise lives 0.3 mile from Keith. The distance that Tim and keith live from

ech other is 0.2 times as great as the distance between Denise and Keith. How
Mathematics
2 answers:
makvit [3.9K]3 years ago
7 0
0.3 * 0.2 = 0.06 miles. :)
Neporo4naja [7]3 years ago
4 0
0.2*0.3 is 0.06
just multiply
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Triangles IJK and LMN are similar. Find y using proportions. Explain and show all your steps.
Deffense [45]

Triangles IJK and LMN are similar. Then, the proportion between their similar sides must be equal. That is:

IJ/ML = JK/MN = IK/LN

where:

IJ = x

JK = 54

IK = y

MN = 42

ML = 28

NL = 35

In order to find the value of y, you consider the equation JK/MN = IK/LN, and solve for y, just as follow

JK/MN = IK/LN replace by the values

54/42 = y/35 multiply both sides by 35

(54/42)(35) = y

45 = y

Hence, y = 45

4 0
11 months ago
Solve for x<br> 3/4+x=1/2<br> Simplify your answer
lukranit [14]

Step 1. Subtract 3/4 from both sides

x = 1/2 - 3/4

Step 2. Simplify 1/2 - 3/4 to -1/4

x = -1/4

7 0
3 years ago
How do I find the equivalent
satela [25.4K]
The equivalent to that is 8.
7 0
3 years ago
Common numbers for 15 18 and 12
Aleks [24]
<span>Common numbers for 15 18 and 12: 1 and 3</span>
8 0
3 years ago
Rabies is an often-fatal disease typically transmitted through the bite of an infected animal. The state of Florida has been rec
slega [8]

Answer:

a) 3.6

b) 1.897

c)0.0273

d) 0.9727

Step-by-step explanation:

Rabies has a rare occurrence and we can assume that events are independent. So, X the count of rabies cases reported in a given week is a Poisson random variable with μ=3.6.

a)

The mean of a Poisson random variable X is μ.

mean=E(X)=μ=3.6.

b)

The  standard deviation of a Poisson random variable X is √μ.

standard deviation=S.D(X)=√μ=√3.6=1.897.

c)

The probability for Poisson random variable X can be calculated as

P(X=x)=(e^-μ)(μ^x)/x!

where x=0,1,2,3,...

So,

P(no case of rabies)=P(X=0)=e^-3.6(3.6^0)/0!

P(no case of rabies)=P(X=0)=0.0273.

d)

P(at least one case of rabies)=P(X≥1)=1-P(X<1)=1-P(X=0)

P(at least one case of rabies)=1-0.0273=0.9727

8 0
2 years ago
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