The inverse of matrix A = ![\left[\begin{array}{cc}2&2&1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%262%261%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
is 
The given matrix is A =
The inverse of a matrix is given by
...(1)
Now, determinant of matrix A is
|A| = 
= (3)(2) - (2)(1)
= 6 - 2
= 4
Now, adjoint A will be
= 3
= -1
= -2
= 2
AdjA =
Now, substituting the values of |A| and AdjA in equation (1), we get
Therefore,
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Answer:
Option number 3: 1,356.48 cm².
Answer:
constant term is -3, the leading term is 3x^3, the coefficient is 3.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
(3 ± √23 * i) /4
Step-by-step explanation:
To solve this, we can apply the Quadratic Equation.
In an equation of form ax²+bx+c = 0, we can solve for x by applying the Quadratic Equation, or x = (-b ± √(b²-4ac))/(2a)
Matching up values, a is what's multiplied by x², b is what's multiplied by x, and c is the constant, so a = 2, b = -3, and c = 4
Plugging these values into our equation, we get
x = (-b ± √(b²-4ac))/(2a)
x = (-(-3) ± √(3²-4(2)(4)))/(2(2))
= (3 ± √(9-32))/4
= (3 ± √(-23))/4
= (3 ± √23 * i) /4
