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alina1380 [7]
3 years ago
9

A classroom contains an equal number of boys and girls. If 5 girls leave, twice as many boys and girls remain. What was the orig

inal number of students present?
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
5 0
The answer is 10 because 5 x 2 is 10
You might be interested in
Which of the following is equivalent to tan 5pie/6?<br>​
nataly862011 [7]

Answer: should be -1/ sqrt of 3. If it asks to rationalize it could be -sqrt of 3/3

Step-by-step explanation:

5 0
2 years ago
What is the value of y in this system of equations: 3x + y = 9 y = –4x + 10 ?
Ahat [919]
<span>3x + y = 9 (I)
</span><span>y = –4x + 10 (II)
------------------------
</span>\left \{ {{3x + y = 9 } \atop {y = -4x + 10 }} \right.

Pass the incognito "4x" to the first term, changing the signal when changing sides.
<span>-------------------------
simplify by (-1)
</span>\left \{ {{3x + y = 9.(-1)} \atop {4x + y = 10 }} \right.<span>

-------------------------
</span>\left \{ {{- 3x - \diagup\!\!\!\!y =-9} \atop {4x + \diagup\!\!\!\!y = 10}} \right.     &#10;
<span>
-------------------------
</span>\left \{ {{- 3x = - 9} \atop {4x = 10}} \right.<span>

-----------
</span>\boxed{x = 1}<span><span>

</span></span><span>Substitute in equation (I) to find the value of "Y".

</span>3x + y = 9 (I)
3*(1) + y = 9
3 + y = 9
y = 9 - 3
\boxed{y = 6}

Answer:
\boxed{\boxed{ \left \ {{x=1} \atop {y=6}} \right. }}

6 0
3 years ago
I have no idea!!! Help??
Savatey [412]

Answer:

x<5

Open circle at 5  going to the left

x >1

Open circle at 1 going to the right

Step-by-step explanation:

7x -19 < 16

Add 19 to each side

7x -19 +19< 16+19

7x< 35

Divide by 7

7x/7 < 35/7

x<5

Open circle at 5  going to the left

9+3x>12

Subtract 9 from each side

9-9 +3x >12-9

3x >3

3x/3 >3/3

x >1

Open circle at 1 going to the right

3 0
3 years ago
Simon drove through some roadworks where the speed limit was 50 mph. Two cameras recorded the time taken to travel 1200 m throug
Tom [10]

Answer:

Speed = 21.43m/s

Step-by-step explanation:

Given

Distance = 1200m -- of the roadworks

Time\ Recorded = 56s

Required

Determine the speed

In this case:

Speed = \frac{Distance\ of\ Roadword}{Time\ Captured}

Speed = \frac{1200m}{56s}

<em></em>Speed = 21.43m/s<em> --- approximated</em>

3 0
3 years ago
Do you know this answer? Please help
ra1l [238]

Step-by-step explanation:

stem = 2

leaf = 9

=> the largest number of tigers = 29

5 0
2 years ago
Read 2 more answers
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