Find the GCD (or HCF) of numerator and denominator
GCD of 18 and 20 is 2
Divide both the numerator and denominator by the GCD
18 ÷ 2
-----------
20 ÷ 2
Reduced fraction:
9
----
10
Question says that there are two type of pans.
First pan has diameter of 9 inches.
Second pan has dimension 8 inches by 11 inches. Which means second pan is rectangular.
It seems you missed few parts of the question like what we have to do with it. I searched for similar question on internet and found that they are finding surface area of the both pans so i will tell you how to find that.
Radius of the circular pan = diameter/2 = 9/2 = 4.5 inches
Then surface area of the first (circular) pan = \pi r^2 = 3.14 *4.5^2 = 63.585 square inches.
Now surface area of second (rectangular) pan is given by formula of area of rectangle
Area = Length * width = 8*11= 88 square inches.
The complete question in the attached figure
we know that
the diagonals of a rhombus intersect to form right angles,
so
angle ACE is ----------> (90°-64°)-----------> 26°
ACE is the angle bisector of ACD, this means that ACD is ---------> 26 x 2 = 52°
The diagonals are angle bisectors to the opposite corners
so
ACD = ACB = 52°
and
BCD = 52 x 2 = 104°
For a rhombus, opposite angles are equivalent,
so
BAD = BCD = 104°
the answer is
angle BAD=104°
Answer:
51 + 29
Step-by-step explanation: