Đề bài sau dùng cho 3 câu từ câu 1 đến 3

The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same

masha68 [24]

Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

Step-by-step explanation:

Let x and y area the random variable that represents the heights of women and men.

Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.

i.e. $\mu_1 = 64$ $\sigma_1=2.7$

Since , $z=\dfrac{x-\mu}{\sigma}$

Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).

[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

$z=\dfrac{72-64}{2.7}=2.96296296\approx2.96$

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.

i.e. $\mu_2 = 69.3$ $\sigma_2=2.8$

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).

[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

$z=\dfrac{70-69.3}{2.8}=0.25$

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

6 0

3 years ago

What is the slope of line that passes through the points -2,4 and 1,-1

GalinKa [24]

Answer:

-5/3

Step-by-step explanation:

-2 to 1 =3 x=3

4 to -1=5 y=-5

y/x slope=-5/3 or -1 2/3

4 0

3 years ago

Will mark brainliest

VMariaS [17]

Answer:

Interquartile range => 7

Third quartile => 22

Range => 13

First quartile => 15

Step-by-step explanation:

Order your data set, from the least amount to the highest amount:

$12, $14, $15, $15, $15, $15, $16, $22, $24, $25

Interquartile range (IQR) = third quartile (Q3) - first quartile (Q1)

Q1 = the middle value of the lower part of the data set, from the median to your left.

Q3 = the middle value of the upper part of the data set, from the median to your right.

The median lies between the 5th and 6th value that is enclosed in the parenthesis below:

$12, $14, ($15), $15, $15,[Median], $15, $16, ($22), $24, $25

The median divides the data set into upper and lower part.

Median = $\frac{15 + 15}{2} = 15$

First quartile: Q1 = $15

Third quartile: Q3 = $22

IQR = $22 - $15 = $7

Range = highest amount - least amount = 25 - 12 = $13

3 0

3 years ago

Jonah drives from his car to and from work. The total length of the trip to and from work is 19.2 miles. In August, Jonah worked

natita [175]

ANSWER

The total length of the trip to and from work in August is

$403.2 \: miles$

EXPLANATION

The total length of the trip to and from work is

$19.2 \: miles$

If Jonah worked 21 days in August,

Then, the total length of the trip to and from work is
$= 21 \times 19.2 \: miles$

Change the decimal to fraction and multiply,

$= 21 \times \frac{192}{10} miles$

$= \frac{21 \times 192}{10}$

$= \frac{4032}{10} miles$

Convert back to decimal

$= 403.2 \: miles$