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IceJOKER [234]
3 years ago
6

Estimate the Circumference of this circle. 10m

Mathematics
1 answer:
Rina8888 [55]3 years ago
7 0

Answer:

62.8

Step-by-step explanation:

10*2=20

20*3.14= 62.8

HOPE IT HELPS

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Story : A Dog’s Tale by Mark Twain

4. Read this sentence from the selection.

“Whenever she heard a large word she said it over to herself many times, and so was able to keep it until there was a dogmatic gathering in the neighborhood.”

In this sentence the word dogmatic is used as —

• an insightful simile
• a descriptive metaphor
• a humorous play on words
• an illuminating allusion


5. In the last paragraph the narrator says his mother would “fetch out a long word.” The connotations of the word fetch remind the reader that the narrator’s mother —

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8. What is ironic about the author’s mother showing off with her knowledge of the word unintellectual?

• Her child knew she didn’t understand the word correctly.

• The strangers all already knew the meaning of the word.

• As any intellectual would know, the word should be “nonintellectual.”

• She did not know any synonyms for the word.


9. Which type of person is most like the author’s mother?

• A high-performing student with an excellent memory for words

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7 0
3 years ago
Read 2 more answers
jake planted trees in a row that 20 feet long. he planted tree at the beginning of the row then he plantyed a tree every 5 feet
Svetradugi [14.3K]
What's the question you're asking
5 0
3 years ago
What is the slope of the line? ​
BlackZzzverrR [31]

Answer:2

Step-by-step explanation:

6 0
3 years ago
(98 pts + Brainliest) Question regarding logarithims and point slope form
bezimeni [28]

You are right in thinking that the base of the logarithm doesn't matter. It only affects the spread of the data points if you were to plot them, but would not ultimately have any effect on the slope of the line (but it would on the y-intercept).

One major discrepancy I'm noticing is in the values you found for \ln\sin\theta. For example, if \sin\theta=0.05, then you should have \ln\sin\theta=\ln0.05\approx=-3.0. Not sure how you got -7.0, and the same goes for the rest of your table of values.

Another thing is that the provided solution suggests you take the average the first and last pairs of consecutive data points, and use these values in the slope formula to obtain the best-fit line's slope. If that's the case, then you should have

\dfrac{\Delta\ln x}{\Delta\ln\sin\theta}=\dfrac{\frac{1.86+1.72}2-\frac{2.65+2.28}2}{\frac{-5.4-5.3}2-\frac{-7.0-6.4}2}=\dfrac{1.79-2.47}{-5.35+6.7}=\dfrac{-0.68}{1.35}\approx-0.5

(i.e. you have to take the average of the given values, then use those averages in the \Delta expressions - but this doesn't significantly affect the slope you found)

Ultimately, I think the problem is that your expression for the slope appears to be \dfrac{\Delta\ln x}{\Delta\ln\sin\theta}, when the solution says it should be the reciprocal. I'm of the opinion that your slope is correct, since the experiment refers to \theta (and hence \sin\theta) as the independent variable, and so \Delta\ln\sin\theta would serve as the "run" and \Delta\ln x would serve as the "rise".

5 0
3 years ago
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