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Finger [1]
3 years ago
5

4r - 10s? can someone please help me with my math homeowrk?

Mathematics
1 answer:
Gwar [14]3 years ago
3 0

Answer:

4r - 10s OR 4r + (-10s)

Step-by-step explanation:

There are no like terms so I can't do anything so the answer remains as 4r - 10s... UNLESS U WANT TO KEEP CHANGE CHANGE AND THEN YOUR FINAL ANSWER WILL BE 4r + (-10s)

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Which equation represents the slope-intercept form of the line below? y intercept: 0, 8 slope : 1/2
Natali [406]

Answer:

y = 1/2 x + 8

Step-by-step explanation:

We are given the y intercept and the slope, so we can write the equation using the slope intercept form

y = mx+b  where m is the slope and b is the y intercept

y = 1/2 x + 8

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3 years ago
What is the Triangle Congruence Theorem and is it congruent?
faust18 [17]

Answer:

Two triangles are congruent if their corresponding sides are equal in length and their corresponding interior angles are equal in measure. We use the symbol ≅ to show congruence. Corresponding sides and angles mean that the side on one triangle and the side on the other triangle, in the same position, match.Step-by-step explanation:

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3 Fred is playing tennis. For every 2 of his serves that land in, 3 serves land out. If he hit 30 serves in, how many serves lan
sineoko [7]

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d

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6 0
3 years ago
Read 2 more answers
(X+5)+(x-5)=56 what does x=?
kirill115 [55]

Answer:

x=28

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

x+5+x−5=56

x+5+x+−5=56

(x+x)+(5+−5)=56(Combine Like Terms)

2x=56

2x=56

Step 2: Divide both sides by 2.

2x/2=56/2

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plz give me brainiest

8 0
3 years ago
Which is not an equation of the line that passes through the points (1, 1) and (5, 5)?
nydimaria [60]

Answer:

Any equation of the line that is different from y=x is the solution to the problem.

Step-by-step explanation:

step 1

Find the slope of the line that passes through the points (1, 1) and (5, 5)

m=(5-1)/(5-1)=1

step 2

Find the equation of the line into slope point form

y-y1=m(x-x1)

we have m=1

(x1,y1)=(1,1)

substitute

y-1=(1)(x-1)

y=x-1+1

y=x

therefore

Any equation of the line that is different from y=x is the solution to the problem.

5 0
3 years ago
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