Make 2 eqn, let a be apples and o be oranges:
1. 5a + 4o = 10
2. 5a + 5o = 11
set up an elimination:
1. minus 2.
5a + 4o = 10
- 5a + 5o = 11
____________
o = 1
sub “o” into one of the eqn
5a + 5(1) = 11
5a = 11-5
5a = 6
a = 6/5
a = 1.2
therefore, an orange costs $1.00 and an apple costs $1.20
Answer:
Step-by-step explanation:
perp. -5
y + 7 = -5(x - 4)
y + 7 = -5x + 20
y = -5x + 13
Answer:
Option A. 5
Step-by-step explanation:
From the question given above, the following data were obtained:
First term (a) = –3
Common ratio (r) = 6
Sum of series (Sₙ) = –4665
Number of term (n) =?
The number of terms in the series can be obtained as follow:
Sₙ = a[rⁿ – 1] / r – 1
–4665 = –3[6ⁿ – 1] / 6 – 1
–4665 = –3[6ⁿ – 1] / 5
Cross multiply
–4665 × 5 = –3[6ⁿ – 1]
–23325 = –3[6ⁿ – 1]
Divide both side by –3
–23325 / –3 = 6ⁿ – 1
7775 = 6ⁿ – 1
Collect like terms
7775 + 1 = 6ⁿ
7776 = 6ⁿ
Express 7776 in index form with 6 as the base
6⁵ = 6ⁿ
n = 5
Thus, the number of terms in the geometric series is 5.
