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bearhunter [10]
3 years ago
15

A woman stands 15 ft from a statue. She looks up at an angle of 60° to see the top of the statue. Her eye level is 5 ft above th

e ground. How tall is the statue to the nearest foot?

Mathematics
1 answer:
Novay_Z [31]3 years ago
4 0

Answer:

31 ft

Step-by-step explanation:

Let the Woman's Eye level be at Band the top of the statue be at C in the attached diagram.

We want to calculate the height CE of the statue.

CE=CD+DE

First we find CD using trigonometry

Tan 60=CD/15

CD=15 X Tan 60

=25.98 ft

DE=AB= 5ft( Sides of a Rectangle)

Therefore the height of the statue

CE=CD+DE = 25.98+5=30.98 ft

=31ft( to the nearest foot)

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What is the probability of drawing the compliment of a king or a
inna [77]

Answer:

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

n( E_{1} ) = 4 _{C_{1} }  = 4

Let E₂ be the event of the card drawn being a queen

n( E_{2} ) = 4 _{C_{1} }  = 4

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability  of drawing of a king or a  queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

                 = \frac{4}{52} + \frac{4}{52}

P( E₁ U E₂ ) = \frac{8}{52}

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards

P(E_{1}UE_{2})  ^{-} = 1- P(E_{1} U E_{2} )

P(E_{1}UE_{2})  ^{-} = 1- \frac{8}{52}

P(E_{1}UE_{2})  ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a  queen from a standard deck of playing cards = 0.846

5 0
2 years ago
Solve x divided by four equals eight . (1 point)<br><br><br> 4<br> −4<br> 32<br> −32
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X/4 = 8 
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3 years ago
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2 years ago
Solve for the given length. The length of a rectangle is 3m longer than its width. The area of the rectangle is 154^2. What is t
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If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
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3 years ago
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