Area of the bigger rectangle =(18×8)cm
2
=144cm
2
Area of the smaller rectangle =((30−18)×(8−6))=(12×6)cm
2
=72cm
2
∴ Total area = area of smaller rectangle + area of bigger rectangle =(72+144)cm
2
=216cm
2
<h3>
Answer: 80 meters</h3>
This is an isosceles triangle. The dashed line is the height which is perpendicular to the base 120. The height is always perpendicular to the base. The dashed line cuts the base into two equal pieces (this only works for isosceles triangles when you cut at the vertex like this).
So we have two smaller triangles each with a base of 60 and a height of x. Focus on one of the right triangles and use the pythagorean theorem to solve for x.
a^2 + b^2 = c^2
x^2 + (60)^2 = (100)^2
x^2 + 3600 = 10000
x^2 = 10000 - 3600
x^2 = 6400
x = sqrt(6400)
x = 80
Each smaller right triangle has side lengths of 60, 80, 100
Note the ratio 60:80:100 reduces to 3:4:5. A 3-4-5 right triangle is a very common pythagorean primitive.
The problem presented with the word used as "divied" is very tricky and misleading to the point that it might create an understanding.
So we will approach this is in two ways.
If this was meant to be "divided by" then it would look like this:
6 / 192
If this was meant to be "divided to" then it would look like this:
192 / 6
Let us first solve for the first possible problem:
6 / 192 = ?
0.0312
0.0312 would be the answer.
Let us then solve for the second possible problem:
192 / 6 = ?
32 = ?
32 would be the answer.
So 0.0312 and 32 would be two possible answers to this problem.
Well, if you put -2 and 2 together, meaning you multiply them, it equals -4.
