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Anni [7]
3 years ago
14

a box contains 10 equal-sized balls, numbered 1 to 10. two balls are drawn at random simultaneously. what is the probability tha

t the numbers on the two balls will differ by more than 2?
SAT
1 answer:
EleoNora [17]3 years ago
3 0

The probability that the two balls are chosen <u>will differ by more than 2</u> is 43/45

Probability is the likelihood or chance that an event will occur.

If a box contains 10 equal-sized balls and 2 balls are chosen at random from the box, the total outcome will be expressed as:

10C_2=\frac{10!}{(10-2)!2!}\\ 10C_2=\frac{10!}{8!2!}\\10C_2=\frac{10\times 9 \times 8!!}{8!2!}\\10C2=\frac{90}{2} =45 ways

If the number on the two balls chosen will<u> differ by less than or equal to 2,</u> the expected outcomes are (1, 2), (1, 3) that is 2 outcomes

The probability that the two balls are chosen will differ by less than or equal to 2 is 2/45

The probability that the two balls are chosen <u>will differ by more than 2</u> is 1 - 2/45 = 43/45

Learn more here: brainly.com/question/13604758

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