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Sphinxa [80]
3 years ago
13

Which equation is an example of the commutative property of multiplication? (4 2i) = (2i 4) (4 2i)(3 – 5i) = (3 – 5i)(4 2i) (4 2

i)(3 – 5i) = (4 2i)(3 – 5i)(1) (4 2i) = (4 2i 0)
SAT
1 answer:
kozerog [31]3 years ago
4 0

Option B is correct. (4 + 2i)(3 – 5i) = (3 – 5i)(4 + 2i) satisfies the commutative property of multiplication

Given two values A and B, according to the commutative property of multiplication;

  • AB = BA

This shows that the product of A and B stays the same no matter the arrangement.

From the given option, we can see that (4 + 2i)(3 – 5i) = (3 – 5i)(4 + 2i) satisfies the commutative property of multiplication where we can say;

A = 4 + 2i and B = 3 - 5i

Learn more here: brainly.com/question/17955280

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Two key principles that form the foundation for an ethical sales presentation are
BigorU [14]

The two key principles that form the foundation for an ethical sales presentation are:

  1. To uncover needs.
  2. To solve problems.

<h3>What is a sales presentation?</h3>

A sales presentation is an act that involves the process of speaking to customers and potential customers, so as to formally share and explain information about a product, especially for the purpose of proffering a solution to a particular problem.

This ultimately implies that, the two key principles that form the foundation for an ethical sales presentation are:

  1. To uncover needs.
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4 0
2 years ago
Golden Gate Park has been a popular setting for gatherings.
allsm [11]
D. A popular setting



7 0
4 years ago
A bat emits a sound at a frequency of 3. 00 × 104 hz as it approaches a wall. The bat detects beats such that the frequency of t
OLga [1]

Taking into account the Doppler efect, the speed of the bat is closest to 5.02 \frac{m}{s}.

The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

f1=f\frac{v+-vR}{v+-vE}

Where:

  1. f1, f: Frequency perceived by the receiver and frequency emitted by the issuer respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s⁻¹)
  2. v: Velocity of propagation of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 340 m/s
  3. vR, vE: Speed ​​of the receiver and the sender respectively. Its unit of measure in the S.I. is the m/s
  4. ±, ∓:
  • We will use the + sign:

In the numerator if the receiver approaches the sender

In the denominator if the sender moves away from the receiver

  • We will use the sign -:

In the numerator if the receiver moves away from the emitter

In the denominator if the sender approaches the receiver

In this case, a bat emits a sound at a frequency of 3.00×10⁴ Hz= 30,000 Hz as it approaches a wall.

The bat detects beats such that the frequency of the echo is 900 hz higher than the frequency the bat is emitting.

So, you know:

  • f1= 30,000 Hz + 900 Hz= 30,900 Hz
  • f= 30,000 Hz
  • v= 340 m/s
  • vE=vR= vbat
  • Receiver approaches the sender

Replacing in the expression is considered the general case of the Doppler effect:

30900 Hz=30000 Hz\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

Solving:

\frac{30900 Hz}{30000 Hz} =\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

1.03=\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}

1.03×( 340\frac{m}{s} -vbat)= 340 \frac{m}{s} + vbat

1.03×340\frac{m}{s} - 1.03×vbat= 340 \frac{m}{s} + vbat

350.2\frac{m}{s} - 1.03×vbat= 340 \frac{m}{s} + vbat

350.2\frac{m}{s} - 340 \frac{m}{s}= vbat + 1.03×vbat

10.2 \frac{m}{s}= 2.03×vbat

10.2 \frac{m}{s}÷ 2.03 = vbat

<u><em>5.02 </em></u>\frac{m}{s}<u><em>= vbat</em></u>

In summary, the speed of the bat is closest to 5.02 \frac{m}{s}.

Learn more about the Doppler effect:

  • brainly.com/question/17107808
  • brainly.com/question/14929897
6 0
2 years ago
How does the amount, or magnitude, of charge on an object affect its attraction or repulsion of another object?
lubasha [3.4K]
The magnitude of an object's charge can either increase or decrease the attraction/ repulsion between another object. The larger the difference of the two object's charges, the stronger opposite charges attract, and the stronger like charges repel.
5 0
4 years ago
John believes that the amount of sleep he gets the night before a test and his score on that test are inversely related. On his
trasher [3.6K]

John will need to sleep for 10.3 hours before  his second exam so that the

average of his two exam scores is an 80.

We were given

8 hours of sleep = 70

To get average of 80

<u>70+ x</u> = 80

  2

Cross multiply:

70+x = 160

x= 160-70

 = 90.

If  8 hours of sleep = 70

       x hours of sleep = 90

Cross multiply

8× 90 = 70 × x

720 = 70x

x = 720/70

x  = 10.2857

    ≈ 10.3 hours of sleep

Read more about Equation here brainly.com/question/17202391

5 0
3 years ago
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