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Lunna [17]
3 years ago
7

HELP ME PLEASE 58.25 is an irrational number. True or false?

Mathematics
1 answer:
Aneli [31]3 years ago
7 0
Irrational numbers don't end
they can't be written in form a/b

obvoisly, 58.25 ends and it can be written as 58.25/1

(repeating decimals can be written in a/b form, it just takes work to find)


false, 58.25 is NOT irrational
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What are the last two digits of 7^1867? ​
Kipish [7]

Considering that the powers of 7 follow a pattern, it is found that the last two digits of 7^{1867} are 43.

<h3>What is the powers of 7 pattern?</h3>

The last two digits of a power of 7 will always follow the following pattern: {07, 49, 43, 01}, which means that, for 7^n, we have to look at the remainder of the division by 4:

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More can be learned about the powers of 7 pattern at brainly.com/question/10598663

3 0
2 years ago
Hernando and Rachel are factoring 2mp-6p+27-9m. Is either of them correct? Explain your reasoning,
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Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as Hernando and Rachel's solution are not provided. So, I will just solve the question directly.

Given

2mp-6p+27-9m

Required

Factor

2mp-6p+27-9m

Group into 2

2mp-6p+27-9m = [2mp-6p]+[27-9m]

Factor each group

2mp-6p+27-9m = 2p[m-3]+9[3-m]

Rewrite 3 - m as -(m-3)

So, we have:

2mp-6p+27-9m = 2p[m-3]-9[m-3]

Factor out m - 3

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3 years ago
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Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
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