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lianna [129]
4 years ago
6

write an equation in point-slope form for the line that has a slope of 15 and contains the point (2,−9).

Mathematics
1 answer:
Lorico [155]4 years ago
6 0

Answer:

  y +9 = 15(x -2)

Step-by-step explanation:

The point-slope form of the equation for a line is ...

  y -k = m(x -h) . . . . . . for slope m and point (h, k)

Here, you are given m=15 and (h, k) = (2, -9). Putting these values into the form gives the equation ...

  y +9 = 15(x -2)

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The point P(5,1) lies on the curve y=5x. If Q is the point (x,5x), find the slope of the secant line PQ for the following values
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Answer:

5

Step-by-step explanation:

We have been given that the point P(1,5) lies on the curve y=5x. Q is the point (x,5x). We are asked to find the slope of the secant line PQ for x=5.1.

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Now, we will use slope formula to find required slope.

m=\frac{y_2-y_1}{x_2-x_1}  

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Using these points in slope formula, we will get:

m_{PQ}=\frac{25.5-5}{5.1-1}=\frac{20.5}{4.1}=5

Therefore, the slope of the line PQ is 5.  

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