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2 years ago

Help plz i give brainliest

Mathematics

2 answers:

kiruha [24]2 years ago

8 0

Volume cube = length to the power 3
v=b^9/125

Natasha_Volkova [10]2 years ago

6 0

Answer: Hope this helps :)

$\frac{1}{5} b^{27}$

<h2><u><em>Mark me as Brainliest please</em></u></h2>

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I need help with these questions please

mr Goodwill [35]

Answer:

a) the graph has a minimum

b) (3, 0)

c) x=3

d) N/A

c) (0, 9)

*forgot how to solve for roots

Step-by-step explanation:

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4 years ago

Read 2 more answers

Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=4, u′(0)=7, v(0)=2 and v′(0)=1. Find the values

Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

$u(0)=4,u'(0)=7,v(0)=2,v'(0)=1$

a.We have to find the values of $\frac{d(uv)}{dx}$

$\frac{d(u\cdot v)}{dx}=u'v+uv'$

Using this formula

Then , we get

$[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18$

$[\frac{d(uv)}{dx}]_{x=0}=18$

b. $\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}$

$[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}$

$[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}$

$[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}$

$[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}$

d. $\frac{d(-6v-9u)}{dx}=-6v'-9u'$

$[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69$

$[\frac{d(-6v-9u)}{dx}]_{x=0}=-69$

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3 years ago

Solve the part that need solving.

amid [387]

dowload this app now hehe:) p.h.o.t.o.m.a.t.h

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3 years ago

What is the probability of drawing a black face card from a standard deck of playing cards?

LiRa [457]

Answer:

The probability is 6/52 = 3/26.

Step-by-step explanation:

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3 years ago

What is the product of -2/5 and -7/10

muminat

Answer:

The answer is 0.28

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3 years ago