6m+23
You have to use distributive property, so 15x2=30 and 2x3m= 6m. You then subtract 30 from 7 and get 23.
<h3>Answer</h3>
First multiply everything by 27

Then approximate the terms with 27 if it's possible (27 and 9) (27 and 27)

So now multiply again

And you have


You're welcome if it's right
Answer:
s = 71 mph, and s+9 = f = 80 mph
Step-by-step explanation:
The distances the two busses travel add up to 604 mi.
Letting f be the faster speed and s the slower. Then f = s + 9 (mph).
Then (s + 9)(mph)(4 hr) + (s)(mph)(4 hr) = 604 mi. Solve this for s:
4s + 36 + 4s = 604 mi, or 8s = 568. Finally, s = 71 mph, and s+9 = f = 80 mph.
Answer:
x = 9.27 cm
Volume = 289.2 cm³
Step-by-step explanation:
SA = Surface Area
SA = 229.2 cm²
P = Perimeter of Base
P = 3(6)
P = 18 cm
H = Height of Solid
H = x
A = Area of Base(Equilateral Triangle)
A = 6²√3 / 4
A = 36√3 / 4
A = 9√3
A = 9(1.732)
A = 31.176
A = 31.2 cm²
SA = Surface Area
SA = PH + 2A
229.2 = 18x + 2(31.2)
229.2 = 18x + 62.4
229.2 - 62.4 = 18x
166.8 = 18x
9.266 = x
9.27 = x
x = 9.27 cm
V = Volume
V = AH
V = 31.2(9.27)
V = 289.224
V = 289.2 cm³
Not sure at all but i think the 18 one