The general form of the line is:
y = mx + c where:
m is the slope
c is the y-intercept
Now, we are given that the slope = 1/2.
The equation now became:
y = (1/2) x + c
Now, we need to get the y-intercept. We are given that (-4 ,1) belongs to the line. Therefore, this point satisfies the equation of the line. Based on this, we will substitute with this point in the equation above and solve for c as follows:
y = (1/2) x + c
1 = (1/2)(-4) + c
1 = -2 + c
c = 1+2
c = 3
Based on the above, the equation of the line is:
y = (1/2) x + 3
Answer:
y = 5 cos ((2π/3)x - 2) + 2
Step-by-step explanation:
Cosine function takes a general form of y = A cos (Bx + C) + D
Where
A is the amplitude
2π/B is the period
C is the phase shift ( if -C, then phase shift right, if +C phase shift left)
D is the vertical displacement (+D is above and -D is below)
Given the conditions of the function to build and the general form, we can write:
** Note: period needs to be 3, so 2π/B = 3, hence B = 2π/3
Now we can write:
y = 5 cos ((2π/3)x - 2) + 2
first answer choice is right.
Answer:
C. 37
Step-by-step explanation:
winindoutpickc
x-y=4 2x+3y=10 find: 3x+2y
FIrst you need to figure out what either x or y equals with one of the equations. It doesn't matter which, because they are dependent on eachother and will both give the same number at the end.
I chose to go with the first equation, because it was simplier, which makes it easier to find the first variable. Again you can solve for either x or y first, I chose x
x-y=4
becomes
x=4+y
now we can plug this x value into the second equation of 2x+3y=10 to find
2(4+y)+3y=10
8+2y+3y=10
8+5y=10
solving for y
5y=2
y=2/5
Now we can plug this y value into the first equation to get an actual value of x
x-(2/5)=4
x=4+2/5
x=22/5
since we now have both x and y values, x=22/5 y=2/5, we can plug them into the 3rd equation to find what it equals
3(x)+2(y)=??
3(22/5)+2(2/5)=??
66/5+4/5=??
70/5=14
