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djverab [1.8K]
3 years ago
7

The endpoints of RS are R: (9,-4) and S: (2, -8).

Mathematics
1 answer:
Vladimir79 [104]3 years ago
7 0

Answer:

B, (11/2,-6)

Step-by-step explanation:

to get the midpoint of two endpoints, simply take the average of each corresponding coordinate

midpoint: ((Rx+Sx)/2,(Ry+Sy/2)).

((9+2/2),(-4+-8/2)) = (11/2,-12/2) = (11/2,-6)

the midpoint formula in general is : ((x+x1)/2),(y+y1)/2))

where x1 is the initial or first x coordinate, y1 is the initial or first y coordinate, x is the second, last, or final x coordinate. and y is the second, last, or final y coordinate.

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QveST [7]
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Answer:

Option B is true

Step-by-step explanation:

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Colby is making a home video consisting of a 5-minute introduction followed by several short skits. Each skit is 6 minutes long.
givi [52]
<h2>Hello!</h2>

The answer is: There are a total of 16 skits in the video.

<h2>Why?</h2>

From the statement, we know that the total length of the video is 101 minutes and it contains a 5-minute introduction, the rest of the minutes are short skits (which are 6 minutes long each one).

So, we need to write the following equations:

First equation:

TotalDuration=Introduction+n*Skit

Second equation:

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Where,

TotalDuration=101Minutes\\Introduction=5Minutes\\n=NumberOfSkits\\Skit=6Minutes

So, replacing and substituting the second equation into the first equation we have:

101Minutes=5Minutes+n*6Minutes\\n*6Minutes=101Minutes-5Minutes\\n*6Minutes=96Minutes\\n=\frac{96Minutes}{6Minutes}=16

So, there are a total of 16 skits in the video.

Let's prove it substituting "n" into the first equation:

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8 0
3 years ago
Cos^2x+cos^2(120°+x)+cos^2(120°-x)<br>i need this asap. pls help me​
o-na [289]

Answer:

\frac{3}{2}

Step-by-step explanation:

Using the addition formulae for cosine

cos(x ± y) = cosxcosy ∓ sinxsiny

---------------------------------------------------------------

cos(120 + x) = cos120cosx - sin120sinx

                   = - cos60cosx - sin60sinx

                   = - \frac{1}{2} cosx - \frac{\sqrt{3} }{2} sinx

squaring to obtain cos² (120 + x)

= \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------

cos(120 - x) = cos120cosx + sin120sinx

                   = -cos60cosx + sin60sinx

                   = - \frac{1}{2}cosx + \frac{\sqrt{3} }{2}sinx

squaring to obtain cos²(120 - x)

= \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

--------------------------------------------------------------------------

Putting it all together

cos²x + \frac{1}{4}cos²x + \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x + \frac{1}{4}cos²x - \frac{\sqrt{3} }{2}sinxcosx + \frac{3}{4}sin²x

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= \frac{3}{2}cos²x + \frac{3}{2}sin²x

= \frac{3}{2}(cos²x + sin²x) = \frac{3}{2}

                 

5 0
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jek_recluse [69]

Answer:

i√17 ≈ 4.123106i

Step-by-step explanation:

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