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3 years ago

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to al rt. thousands period ones period ones hundred thousands ten thousands one thousands tens hundreds 4 0 5 х 3 6 Х What I Mul

tiply

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monitta3 years ago

7 0

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There are 416 students who are enrolled in an introductory geology course. if there are seven boys to every six girls, how many

Alenkinab [10]

$\text{Let the number of boys be x and number of girls be y.}\\
\\
\text{and there are total 416 students enrolled in the course. so we have}\\
\\
x+y=416 \ \ \ \ \ \ \ \ \ \ ......(i)\\
\\
\text{also given that there are seven boys to every six girls, that is}\\
\\
\frac{x}{y}=\frac{7}{6}$

$\Rightarrow 6x=7y\\
\\
\Rightarrow y=\frac{6x}{7}\\
\\
\text{substitute this value of y in (i), we get}\\
\\
x+\frac{6x}{7}=416\\
\\
\Rightarrow \frac{7x+6x}{7}=416\\
\\
\Rightarrow \frac{13x}{7}=416\\
\\
\Rightarrow x=\frac{416\times 7}{13}\\
\\
\Rightarrow x=224$

Hence the number of boys in the course are: 224

4 0

3 years ago

A sanitary landfill has available space of 16.2 ha at an average depth of 10 m. Seven hundred sixty-five (765) cubic meters of s

AfilCa [17]

Answer:

16.3 years

Step-by-step explanation:

1 ha = 10,000 m^2

The total capacity of the landfill is:

$C = 16.2*10,000*10 = 1,620,000\ m^3$

If waste is compacted to twice its delivered density, its volume is half of the delivered volume. Assuming that a year has 52 weeks, the volume of compacted solid waste dumped per year is:

$V=52*(5*0.5*765)\\V=99,450\ m^3$

The expected life of the landfill is given by its capacity divided by the yearly volume:

$L=\frac{C}{V}=\frac{1,620,000}{99,450} \\L=16,3\ years$

The landfill has an expected life of 16.3 years.

6 0

3 years ago

Solve the equation for t A=s(t+r)x

tester [92]

Answer:

t = (A/sx) - r

Step-by-step explanation:

Solve for t like this:

$A = s(t+r)x\\A = sx(t+r)\\\\\frac{A}{sx} = t+r\\\frac{A}{sx} - r = t\\t= \frac{A}{sx} - r$

6 0

3 years ago

Multiply. Enter the product in simplest form.<br> 17/8 x 14/51

jasenka [17]

Answer:

7/12 or in decimal form it is .583

Step-by-step explanation:

Please mark brainliest!

hope this helps!

7 0

3 years ago

Find cos(2115°) and sin(2115°). Identify the measure of the reference angle.

ivolga24 [154]

Answer:

Cos(2115°) =1/√2

Sin(2115°) = -1/√2

Step-by-step explanation:

We have to find the values of Cos (2115°) and Sin (2115°).

Now, 2115° can be written as (23×90°+ 45°).

Therefore, the angle 2115° lies in the 4th quadrant where Cos values are positive and Sin values are negative.

Hence, Cos (2115°) = Cos(23×90° +45°) =Sin 45° {Since 23 is an odd number, so the CosФ sign will be changed to SinФ} =1/√2 (Answer)

Again, Sin (2115°) = Sin(23×90° +45°) = -Cos 45° {Since 23 is an odd number, so the SinФ sign will be changed to CosФ} = -1/√2 (Answer)

Now, the required reference angle is 45°. (Answer)

8 0

3 years ago