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2 years ago

Jorge is hiking a trail that is 2½ miles long. He hikes 13 miles before resting.

Mathematics

1 answer:

scZoUnD [109]2 years ago

3 0

By taking a difference between mixed numbers, we can conclude that the distance left is 5/8 of a mile.

<h3>How much farther does he have to hike?</h3>

We know that the total length of the trail is 2½ miles, and Jorge hikes 1⁷/₈ miles before resting.

So the distance that he has left is equal to the difference between 2½ miles and 1⁷/₈ miles.

Remember that the mixed numbers can be rewritten as:

2½ = 2 + 1/2

1⁷/₈ = 1 + 7/8

So we need to find the difference:

(2 + 1/2) - (1 + 7/8) = ( 2 - 1) + (1/2 - 7/8)

= 1 + (4/8 - 7/8) = 1 - 3/8

Now we can simplify this so we get a single fraction:

1 - 3/8 = 8/8 - 3/8 = 5/8

From this, we can conclude that the distance left is 5/8 of a mile.

If you want to learn more about mixed numbers:

brainly.com/question/1746829

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The prime factor of 180

alisha [4.7K]

Answer: 5*2*2*3*3

Step-by-step explanation:

First you divide 180 by 2 and you get 90. Then you proceed to divide that by 2 again and get 45. You will then divide 45 by 3 to get 15. Then divide 15 by 3 again and get 5, which cannot be divided any smaller.

180/2=90

90/2=45

45/3=15

15/3=5

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3 years ago

Which expressions are equivalent to 2(4x−3)+3x−12(4x−3)+3x−1

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3 years ago

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Three cards are drawn from a standard deck of 52 cards without replacement. Find the probability that the first card is an ace,

MrRissso [65]

Answer:

$4.82\cdot 10^{-4}$

Step-by-step explanation:

In a deck of cart, we have:

a = 4 (aces)

t = 4 (three)

j = 4 (jacks)

And the total number of cards in the deck is

n = 52

So, the probability of drawing an ace as first cart is:

$p(a)=\frac{a}{n}=\frac{4}{52}=\frac{1}{13}=0.0769$

At the second drawing, the ace is not replaced within the deck. So the number of cards left in the deck is

$n-1=51$

Therefore, the probability of drawing a three at the 2nd draw is

$p(t)=\frac{t}{n-1}=\frac{4}{51}=0.0784$

Then, at the third draw, the previous 2 cards are not replaced, so there are now

$n-2=50$

cards in the deck. So, the probability of drawing a jack is

$p(j)=\frac{j}{n-2}=\frac{4}{50}=0.08$

Therefore, the total probability of drawing an ace, a three and then a jack is:

$p(atj)=p(a)\cdot p(j) \cdot p(t)=0.0769\cdot 0.0784 \cdot 0.08 =4.82\cdot 10^{-4}$

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4 years ago

Evaluate the expression 1/3 (4+18)-2 2nd degree

Ulleksa [173]

Answer: 10/3

Explanation:

I will rewrite the expression using the math editor just to make it more understandable.
<span />
$( \frac{1}{3} )(4+18)-2^2$

Now, I will show the solution step-by-step

1) Solve the parenthesis:

=> $\frac{1}{3} .22-2^2$

2) Calculate the product of the fraction 1/3 times number 22 and rais 2 to the power 2:

=> <span> $\frac{1.22}{3.1}-4 = \frac{22}{3}-4$

3) Subtract 4 from the fraction 22/3

$\frac{22}{3} -4= \frac{22-4.3}{3} = \frac{22-12}{3} = \frac{10}{3}$ </span>

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4 years ago

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kozerog [31]

Answer:

use substitution

(5 x 7) - (3 x 8) + 11= 35 - 24 + 11= 22

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3 years ago