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Alchen [17]
2 years ago
13

In a graph Y/x+m=c gggggggggggggggggg

Mathematics
1 answer:
alexdok [17]2 years ago
8 0

Answer:

c=ywx in graph y×x+m the solution is this

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Peter was thinking of a number. Peter divides by 7, then adds 5 to get an answer of 13. What was the original number?
Mila [183]

Answer:

56

Step-by-step explanation:

5-13=8

7*8=56

7 0
3 years ago
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Find the value of x and y
velikii [3]

Answer:

2x + 20 = 3x-10

2x -3x = -20-10

-x = -30

x= 30

Checking part:

2x+20 = 2(30) +20 = 60+20 = 80

3x-10 = 3(30) - 10 = 90-10 = 80

Hence, the final answer is x = 30.

Step-by-step explanation:

6 0
3 years ago
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What number would represent the outlier in the following set of data?
Rom4ik [11]

Answer:

What number would represent the outlier in the following set of data?

10, 13, 9, 29, 15, 11, 14, 8, 10, 11, 17, 14, 12

17

13

29

8

Step-by-step explanation:

5 0
3 years ago
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Let X denote the time in minutes (rounded to the nearest half minute) for a blood sample to be taken. The probability mass funct
Basile [38]

This question is incomplete, the complete question is;

Let X denote the time in minutes (rounded to the nearest half minute) for a blood sample to be taken. The probability mass function for X is:

x     0       0.5       1       1.5       2       2.5

f(x)  0.1     0.2     0.3    0.2     0.1       0.1

determine;

a) P( X < 2.5 )

B) P( 0.75 < X ≤ 1.5 )

Answer:

a) P( X < 2.5 ) = 0.9

b) P( 0.75 < X ≤ 1.5 ) = 0.5

Step-by-step explanation:

Given the data in the question;

The probability mass function for X is:

x     0       0.5       1       1.5       2       2.5

f(x)  0.1     0.2     0.3    0.2     0.1       0.1

a) P( X < 2.5 )

P( X < 2.5 ) = p[ x = 0 ] + p[ x = 0.5 ] + p[ x = 1 ] + p[ x = 1.5 ] + p[ x = 2 ]

so

P( X < 2.5 ) = 0.1 + 0.2 + 0.3 + 0.2 + 0.1

P( X < 2.5 ) = 0.9

b) P( 0.75 < X ≤ 1.5 )

P( 0.75 < X ≤ 1.5 ) = p[ x = 1 ] + p[ x = 1.5 ]

so

P( 0.75 < X ≤ 1.5 ) = 0.3 + 0.2

P( 0.75 < X ≤ 1.5 ) = 0.5

3 0
3 years ago
Which equation would best help solve this problem? Five added to 3 times a number is equal to 8 less than 5 times the number.
vitfil [10]
\hbox{five added to 3 times a number = to 8 less than 5 times the number} \\\\ \implies \boxed{5+3x=8-5x}
4 0
3 years ago
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