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jasenka [17]
3 years ago
7

Round to three decimal places 5 = ____ liters

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

The value of 5 quarts to litres is 5.283 litres

To<u> convert quarts to litres</u>, we will use the conversion below:

  • 1 litres= 0.946353 quarts

To convert 5 quarts to litres, we can express this as:

  • x = 5 quarts

Divide both equations to get the value of x

1/x = 0.946353/5

Cross multiply

0.946353x = 5

x = 5/0.946353

x = 5.28344

Convert the result to 3 decimal places

x ≈ 5.283 litres

Hence the value of 5 quarts to litres is 5.283 litres

Learn more on conversion here: brainly.com/question/18141073

Complete question

<em>Convert. Round to 3 decimal places.  </em>

<em>5 quarts ≈ ___ liters</em>

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Answer:

Third option

x ≠2 and x cannot be any value for which v(x) = 0

Step-by-step explanation:

In this problem we are asked to find the domain of the function

(UoV)(x)

We know that (UoV)(x) = U(V(x)).

We know that:

Domain of U(x) is all real numbers except <em>x = 0</em>

Domain of V(x) is all real numbers except <em>x = 2</em>.

Then the domain of the composite function U(V (x)) is:

all real numbers except <em>x = 2</em>. (since <em>x = 2</em> does not belong to the domain of V(x) and all values of x for which <em>V(x) = 0</em> (since <em>x = 0</em> does not belong to the domain of U(x))

Finally the domain of (UoV)(x)) is:

x \neq 2 and V(x) \neq 0

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Use the linear combination method to solve the system of equations.
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For a system of equations to have no real solution, the lines of the equations must be parallel to each other. The solution of the system of equation is (-3.4, -9).

<h3>What is the system of equations?</h3>

Inconsistent System

For a system of equations to have no real solution, the lines of the equations must be parallel to each other.

Consistent System

1. Dependent Consistent System

For a system of the equation to be a Dependent Consistent System, the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

For a system of the equation to be an Independent Consistent System, the system must have one unique solution for which the lines of the equation must intersect at a particular.

Add the two equations,

–2.1x + 4y + 2.1x – 5.5y = –0.2 + 5.3

-2.1x + 2.1x + 4y -5.5y = 5.1

-1.5 y = 5.1

y = 5.1/1.5

y = -3.4

Now, substitute the value of y in any one of the equation, therefore,

-2.1x + 4y = 5.3

-2.1x + 4(-3.4) = 5.3

-2.1x - 17.36 = 5.3

-2.1x = 22.66

x = -9

Hence, the solution of the system of equation is (-3.4, -9).

Learn more about the System of equations:

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4x - 5y + 2xy = 0<br> Can Someone do this for me? I need help.
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Step-by-step explanation: coz I juss know

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Find the equation of the line with a slope of 1/5 that passes through the point (10,9).
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Answer:

The equation of the line with a slope of 1/5 that passes through the point (10,9) is:

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Step-by-step explanation:

Given

Slope = m = 1/5

Point (10, 9)

To Determine

An equation of the line with a slope of 1/5 that passes through the point (10,9).

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

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substituting the values m = 1/5 and the point (10, 9) in the equation

y-y_1=m\left(x-x_1\right)

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Add 9 to both sides

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y=\frac{1}{5}x-2+9

y=\frac{1}{5}x+7

Therefore, the equation of the line with a slope of 1/5 that passes through the point (10,9) is:

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