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neonofarm [45]
3 years ago
12

Help plsssssssssssssssssssssss

Mathematics
1 answer:
sveta [45]3 years ago
8 0

Answer:

Step-by-step explanation:

um

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Write the complex number in the form a + bi.
bonufazy [111]

Answer:

\frac{3}{2} + \frac{3\sqrt{3} }{2} i

Step-by-step explanation:

Using the exact value

cos60° = \frac{1}{2} and sin60° = \frac{\sqrt{3} }{2}, then

3(cos60° + isin60°)

= 3( \frac{1}{2} + \frac{\sqrt{3} }{2} i) ← distribute by 3

= \frac{3}{2} + \frac{3\sqrt{3} }{2} i ← in the form a + bi

7 0
4 years ago
Circle O has a circumference of 132 feet. What is the approximate area of a circle O?
Archy [21]

Answer:1387.96

Please mark me as Brainliest!

Step-by-step explanation:

5 0
4 years ago
HELLOOOO HELP PLEASE
MA_775_DIABLO [31]

Answer:

2*log(x)+log(y)

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

   log_ba^c=c*log_ba

   So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: log_ba=x\implies b^x=a

   Now if we raise both sides to the power of c, we get the following equation: (b^x)^c=a^c

   Using the exponential identity: (x^a)^c=x^{a*c}

    We get the equation: b^{xc}=a^c

    If we convert this back into logarithmic form we get: log_ba^c=x*c

    Since x was the basic logarithm we started with, we substitute it back in, to get the equation: log_ba^c=c*log_ba

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

    log_b{ac}=log_ba+log_bc

    Now for a quick proof, let's just say: x=log_ba\text{ and }y=log_bc

    Now rewriting them both in exponential form, we get the equations:

    b^x=a\\b^y=c

    We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

    b^x*b^y=a*c

   Using the exponential identity: x^{a}*x^b=x^{a+b}, we can rewrite the equation as:

 

   b^{x+y}=ac

   taking the logarithm of both sides, we get:

   log_bac=x+y

   Since x and y are just the logarithms we started with, we can substitute them back in to get: log_bac=log_ba+log_bc

Now let's use these identities to rewrite the equation you gave

log(x^2y)

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

log(x^2)+log(y)

Now using the logarithm of a power to rewrite the log(x^2) we get:

2*log(x)+log(y)

3 0
2 years ago
6.<br> 5x – 2y = 17<br> 2x + 3y = 3<br><br> How do i do elimination on this problem.
kolbaska11 [484]

Answer:

Add the equations in order to solve the first variable. Plug this value into the other equation in order to solve the remaining variables.

The point form is (3,-1)

The equation form is x = 3, y = -1

Hope this helps!

<u><em>PLEASE, </em></u>consideer brainliest. I only have 3 left and then my rank will go up.

3 0
3 years ago
if u play ro-b-lox blox-burg, answer!! dont answer if u dont.. but is it fair if i say abc tk help me make snowmans and each sno
Papessa [141]

Answer:

You probably should have gave them 2/3 of what they did. I wouldn't call you a scammer, but it was not fair.

3 0
3 years ago
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