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kakasveta [241]
3 years ago
14

Solve for x. x/m-x/n=1/p

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
5 0
I hope this helps you

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At a movie theatre adult tickets cost $10 and child ticjets cost $6. Which equation can be used to find s, the number of dollars
timurjin [86]

Answer:

s = 10k + 30

Step-by-step explanation:

Cost of Adults ticket = $10 per adult

Cost of Ticket = $6 per child

Number of adults = k

Number of Children = 5

s = Total cost

Total cost = (Cost per adult * number of adults) + (Cost per child * Number of children)

s = ($10 * k) + ($6 * 5)

s = $10k + $30

s = 10k + 30

4 0
3 years ago
If you can buy 1⁄3 of a box of chocolates for 6 dollars, how much can you purchase for 4 dollars?
alukav5142 [94]

Answer:

2/9 boxes.

Step-by-step explanation:

6 / 1 / 3 = 4 / b

Cross multiply the two

6b = 4/3

Multiply 1/6 on each side

B = 4 /18

It can be reduced to 2/9.

Feel free to let me know if you need more help! :)

5 0
3 years ago
7.
pantera1 [17]

(2h – 3)(3h + 4) is the same thing as

2h(3h + 4) - 3(3h + 4)

6h^2 + 8h - 9h - 12

6h^2 - h - 12

Answer B.

4 0
3 years ago
Read 2 more answers
Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv
liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0
3 years ago
The probability of a train arriving on time and leaving on time is 0.8. The probability of the same train arriving on time is 0.
lys-0071 [83]
To help you with this topic, I would suggest you revise probability trees.

P(train arriving) = 0.8
P(train arriving on time) = 0.84
P(train arriving late) = 0.86

0.8 x 0.86 = 0.688

Answer: 0.688

Hope it helped :)
8 0
3 years ago
Read 2 more answers
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